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- Question
- Ajay takes some loan from Rashmi at the rate of 5% per annum andd after 2 yr, Ajay gave back ? 8800 to Rashmi and this way paid his whole loan. Find the interest by Ajay.
Options- A. ? 825
- B. ? 975
- C. ? 800
- D. ? 850
- Correct Answer
- ? 800
ExplanationHere, A = ? 8800, T =2 yr, R = 5%
We know
SI = ART/(100 + RT) = (8800 x 5 x 2) / (100 + 5 x 2)
= (8800 x 10) / 110
= ? 800 - 1. Rajnish invested certain sum in three different schemes P, Q and R with the rates of interest 10% per annum, 12% per annum and 15% per annum, respectively. If the total interest accrued in 1 yr was ? 3200 and the amount invested in scheme R was 150% of the amount invested in scheme Q. what was the amount invested in scheme Q?
Options- A. ? 8000
- B. ? 9000
- C. ? 5000
- D. ? 3050 Discuss
- 2. A persom invests ? 12000 as fixed deposit at a bank at the rate of 10% per annum simple interest. But due to some pressing needs, he has to withdraw the entire money after 3 yr for which the bank allowed him a lower rate of interest. If he gets ? 3320 less than, what he would have got at the end of 5 yr the rate of interest allowed by bank is
Options- A. 78/9%
- B. 87/9%
- C. 78/9%
- D. 77/9% Discuss
- 3. Mr. Pawan invests an amount of ? 242000 at the rate of 4% per annum for 6 yr to obtain a simple interest, later he invests the principal amount as well as the amount obtained as simple interest for another 4 yr at the same rate of interest. What amount of simple interest will be obtained at the end of the last 4 yr?
Options- A. ? 4800
- B. ? 4850.32
- C. ? 4801.28
- D. ? 4700 Discuss
- 4. Reena had ? 10000 with her, out of this money she lent some money to Akshay for 2 yr at 15% simple interest. She lent remaining money to Brijesh for an equal number of years at the rate of 18%. After 2 yr Reena found that Akshay had given her 360 more as interest as compared to Brijesh. The amount of money which Reena had lent to Brijesh must be
Options- A. ? 4000
- B. ? 2500
- C. ? 3500
- D. ? 4200 Discuss
- 5. Neeta borrowed some money at the rate of 6% per annum for the first 3 yr. at the rate of 9% per annum for the next 5 yr and a the rate of 13% per annum for the period beyond 8 yr. If she pays a total interest of ? 8160 at the and of 11 yr how much money did she borrow?
Options- A. ? 12000
- B. ? 10000
- C. ? 8000
- D. Data is inadequate Discuss
- 6. The difference between the compound interest and the simple interest on a certain sum at 5% per annum for 2 years is Rs. 1.50. The sum is?
Options- A. Rs. 600
- B. Rs. 500
- C. Rs. 400
- D. Rs. 300 Discuss
- 7. If the compound interest on a certain sum for 2 years at 12.5% per annum is 170, the simple interest is?
Options- A. Rs. 150
- B. Rs. 152.50
- C. Rs. 160
- D. Rs. 162.50 Discuss
- 8. A sum amounts to Rs. 1352 in 2 years at 4% compound interest.The sum is?
Options- A. Rs. 1300
- B. Rs. 1250
- C. Rs. 1260
- D. Rs. 1200 Discuss
- 9. Rs. 800 at 5% per annum compound interest will amount to Rs. 882 in?
Options- A. 1 years
- B. 2 years
- C. 3 years
- D. 4 years Discuss
- 10. The compound interest on Rs. 2800 for 1 1/ 2 years at 10% per annum is?
Options- A. Rs. 441.35
- B. Rs. 436.75
- C. Rs. 434
- D. Rs. 420 Discuss
Simple Interest problems
Search Results
Correct Answer: ? 5000
Explanation:
Let a, b and c be the amount invested in schemes P, Q and R, respectively.
Then, according to the question,
[(a x 10 x 1)/100] + [(b x 12 x 1)/100] + [(c x 15 x 1)/100] = 3200
? 10a + 12b + 15x = 320000 .....(i)
Now, c = 240% of b = 12b/5 ....(ii)
and c = 150% of a = 3a/2
? a = 2c/3 = (2/3 x 12/5) b = 8b/5 .....(iii)
From Eqs. (i), (ii) and (iii), we get
16b + 12b + 36b = 320000
? 64b = 320000
? b = 5000
? Sum invested in scheme Q = ? 5000
Correct Answer: 77/9%
Explanation:
Let the rate of interest allowed by bank be r%
According to the question,
[(12000 x 5 x 10)/100] - [(12000 x 3 x r)/100] = 3320
? 6000 - 360r = 3320
? 360r = 6000 - 3320 = 2680
? r = 2680/360 = 74/9%
Correct Answer: ? 4801.28
Explanation:
In the case I,
SI = (P x R x T) /100 = (24200 x 4 x 6) / 100 = ? 5808
? Amount = Principal + SI
SI = 24200 + 5808 = 30008
In the case II,
SI = (30008 x 4 x 4) / 100 = ? 4801.28
Correct Answer: ? 4000
Explanation:
Let the money lent to Akshay = ? P
Then, money lent to Brijesh = ? (10000 - P) [as total amount = ? 10000]
SI for Akshay = (P x 15 x 2)/100 = 3P/10
SI for Brijesh = {(10000 - P) x 18 x 2}/100 = 9/25 (10000 - P)
According to the given condition, (3P/10) - [(9/25) x ( 10000 - P ) = 360
[as SI (Akshay) - SI (Brijesh) = 360]
? (3P/10) - 3600 + 9P/25 = 360
? 3P/10 + 9P/25 = 360 + 3600 = 3960
? 33P/50 = 3960
? P = 3960 x 50/33
? P = 6000
? The amount of money lent to Brijesh
= 10000 - 6000 ? 4000
Correct Answer: ? 8000
Explanation:
Let the sum borrowed = P
Then, according to the question,
[(P x 6 x 3)/100] + [(P x 9 x 5)/100] + [(P x 13 x 3)/100] = 8160
? (18P + 45P +39P) / 100 = 8160
? 102P/100 = 8160
? P = (8160 x 100)/102
? P = ? 8000
Correct Answer: Rs. 600
Explanation:
Let the sum be Rs . 100 then
S.I. = Rs.(100 x 5 x 2/100)= Rs. 10
C.I = Rs. [{100 x (1 + 5/100)2} - 100] = Rs. 41/4
? Difference between C.I and S.I = Rs. (41/4 - 10) = Re. 0.25
? 0.25 : 150 : : 100 : P
? P = (1.50 x 100) / 0.25 = Rs. 600
Correct Answer: Rs. 160
Explanation:
Let the principle is P
so compound interest = p x ( 1 + (12.5/100))sup>2 - p = 170
? p x (112.5/100) x (112.5/100) - p = 170
? P [ 12656.25 - 10000 ] = 170 x 10000
? p = (170 x 10000) / 2656.25
Simple interest SI = (P x T x R )/100
= [{(170 x 10000) / 2656.25} x 2 x 12.5] / 100
= 160
Correct Answer: Rs. 1250
Explanation:
Let the sum be P.
Then, 1352 = P(1 +4/100)2
? 1352 = P x 26/25 x 26/25
? P = (1352 x 25 x 25) / (26 x 26) = 1250
? Principal = Rs. 1250
Correct Answer: 2 years
Explanation:
Let time be t years
? 882 = 800( 1 +5/1000)t
? 882/800 = (21/20)t
? (21/20)2 = (21/20)t
? t =2
? Time = 2years
Correct Answer: Rs. 434
Explanation:
? Final Amount = Rs.[2800 x (1 + 10/100) x (1 +5/100)]
= Rs. [ 2800 x 11/10 x 21/20 ]
= Rs. 3234
? Required C.I. = Rs.(3234 - 2800) = Rs .434
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