Given, A1 = ? 1350, A2 =? 1620
T1 = 5 yr and T2 = 8 yr
Let principal amount be ? P.
? In time = 8 - 5 = 3 yr
Simple interest will be
1620 - 1350 = ? 270
? R = [(A2 - A1 ) x 100] / [A1 T2 - A2 T1]
= [(1620 - 1350) x 100] / [(1350 x 8) - (1620 X 5)]
= (270 x 100)/[10800 - 8100]
= 27000/2700
? R = 10%
? P = (SI x 100) / (R x T)
= (270 x 100) / (10 x 3)
= ? 900
47/10000 = .0047
.02 =(2/100) x 100% =2%
Let N / 11 = 233
Then, N = 233 x 11 = 2563
? Missing digit is 5.
121012 = 12 x 10084 + 4
? remainder = 4
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
Subtract 20, 25, 30, 35, 40, 45 from successive numbers. So 0 is wrong.
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