Given, T1 = 5 yr, R1 = 10% and
T2 = 10 yr, R2 = 8%
Let the first part = P
Then, second part = (1521 - P)
Now, according to the question.
[(P x 5 x 10)/100] = [{(1521 - P) x 10 x 8}/100]
? 5P = 12168 - 8P
? 13P = 12168
? P = ? 936
So second part = 1521 - 936 = ? 585
Last number of given series must be 92 not 91.
? D/(8 - 2) + D/(8 + 2) = 32/60
? D/6 + D/10 = 32/60
? 10D + 6D = 32
? D = 2 km
Sum of first n even numbers = n( n +1 )
Given n = 84
? Required sum = 84 ( 84 + 1 )
= 84 x 85
= 7140
H.C.F. of 42 and 63 is 21.
? H.C.F of 21 and 140 is 7
? H.C.F. of 42, 63 and 140 is 7
As per the formula,
Average of the cubes os 1st 'n' natural numbers= n(n+1)2/4
where, n= 5.
? Required average = 5(5+1)2/4
= (5 x 36)/4 = 5 x 9= 45
Speed = | ❨ | 240 | ❩m/sec = 10 m/sec. |
24 |
∴ Required time = | ❨ | 240 + 650 | ❩sec = 89 sec. |
10 |
The value of | (0.96)3 - (0.1)3 | is: |
(0.96)2 + 0.096 + (0.1)2 |
Given expression |
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