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- Question
- The difference of simple interest from two banks for ? 1000 in 2 yr is ? 20. Find the difference in rates of interest.
Options- A. 2%
- B. 1.5%
- C. 1%
- D. 2.5%
- Correct Answer
- 1%
ExplanationLet the two rates be R1 and R2
According to the question,
[(1000 x 2 x R1)/100] - [(1000 x 2 x R2)/100] = 20
? [2000 x (R1 - R2)] / 100 = 20
? R1 - R2 = 20/20 = 1% - 1. A sum becomes two fold in 6 yr at a certain rate of interest. Find the time, in which the same mount will be 10 fold at the same rate of interest.
Options- A. 35 yr
- B. 49 yr
- C. 59 yr
- D. 54 yr Discuss
- 2. A sum becomes 6 fold at 5% per annum. At what rate, the sum becomes 12 fold?
Options- A. 10%
- B. 12%
- C. 9%
- D. 11% Discuss
- 3. A sum was invested for 4 yr at a certain rate of simple interest. If it had been invested at 2% more annual rate of interest, then ? 56 more would have been obtained. What is the sum?
Options- A. ? 680
- B. ? 700
- C. ? 720
- D. ? 820 Discuss
- 4. For a certain sum, the simple interest in 2 yr at 8% per annum is ? 110 more than the simple interest in 1 yr at the ratio of 5% per annum for the same sum. Find the sum.
Options- A. ? 5000
- B. ? 1000
- C. ? 1050
- D. ? 950 Discuss
- 5. Simple interest for the sum of ? 1230 for 2 yr is ? 10 more than the simple interest for ? 1130 for the same duration. Find the rate of interest.
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Options- A. 5%
- B. 6%
- C. 8%
- D. 2% Discuss
- 6. Raju lent ? 400 to Ajay for 2 yr and ? 100 to Manoj for 4 yr and received from both ? 60 as collective interest, Find the rate of interest, simple interest being calculated.
Options- A. 5%
- B. 6%
- C. 8%
- D. 9% Discuss
- 7. 2/3 part of my sum is lent out at 3%, 1/6 part is Lent out at 6% and remaining part is lent out 12% All the three parts are lent out at simple interest. If the annual income is ? 25, what is the sum?
Options- A. ? 500
- B. ? 650
- C. ? 600
- D. ? 450 Discuss
- 8. Suresh borrowed ? 800 at 6% and Naresh borrowed ? 600 at 10% After how much time will they both have equal debts?
Options- A. 151/3 yr
- B. 141/2 yr
- C. 181/3 yr
- D. 162/3 yr Discuss
- 9. A sum of ? 1521 lent out two parts in such a way that the interest on one part at 10% for 5 yr is equal to that of another part at 8% for 10 yr. What will be the two parts of sum?
Options- A. ? 926 and ? 595
- B. ? 906 and ? 615
- C. ? 916 and ? 605
- D. ? 936 ? 585 Discuss
- 10. Rashim lent ? 600 to Geeta for 2 yr and ? 150 to Seeta 4 yr and received altogether ? 80 as simple interest from both. Find the rate of interest.
Options- A. 34/9%
- B. 24/9%
- C. 54/9%
- D. 44/9% Discuss
Simple Interest problems
Search Results
Correct Answer: 54 yr
Explanation:
Here, n = 2, m =10, T1 = 6 yr, T2 = ?
? T2 = [(m - 1) / (n - 1)] x T1
= [(10 - 1)/(2 - 1)] x 6
= 54 yr
Correct Answer: 11%
Explanation:
SI at 5% = 6P - P = 5P
? 5P = (P x 5 x T) /100
? T = 100 yr
Now, for new rate (R),
11P = (P x R x 100)/100
? R =11%
Correct Answer: ? 700
Explanation:
According to the question
[P x (R + 2) x 4]/100 - [P x R x 4]/100 = 56
? (4PR + 8P - 4PR)/100 = 56
? 8P/100 = 56
? P = (56 x 100)/8 = ? 700
Correct Answer: ? 1000
Explanation:
Given, SI1 - SI2 = 110,
T1 = 2 Yr,
T2 = 1 yr, R1 = 8%, R2 = 5%
According to the question,
[(P x 8 x 2)/100] - [(P x 5 x 1)/100] = 110
? 11P/100 = 110
? P = ? 1000
Correct Answer: 5%
Explanation:
According to the question,
[(1230 x 2 x R)/100] - [(1130 x 2 x R)/100] = 10
? (200 x R)/100 = 10
? R = 5%
Correct Answer: 5%
Explanation:
Let rate is R%
According to the question.
[(R x 400 x 2)/100] + [(R x 100 x 4)/100] = 60
? 12R = 60
? R = 60/12 = 5%
Correct Answer: ? 500
Explanation:
Let entire sum = P
According to the question,
[(2P/3) x 3%] + [(P/6) x 6%] + [1 - ( 2/3 + 1/6 )] P x 12% = 25
? [(2P/3) x (3/100)] + [(P/6) x (6/100)] + [1 - 4 + 1/6] x (12P/100) = 25
? 2P/100 + P/100 + 2P/100 = 25
? 5P = 2500,
? P = 500
Correct Answer: 162/3 yr
Explanation:
Given, R1 = 6% R2 = 10%
According to the question,
800 + [(800 x 6 x T)/100] = 600 + [(600 x 10 x T)/100]
800 + 48T = 600 + 60T
? 12T = 200
? 3T = 50
? T = 50/3 = 162/3 yr
Correct Answer: ? 936 ? 585
Explanation:
Given, T1 = 5 yr, R1 = 10% and
T2 = 10 yr, R2 = 8%
Let the first part = P
Then, second part = (1521 - P)
Now, according to the question.
[(P x 5 x 10)/100] = [{(1521 - P) x 10 x 8}/100]
? 5P = 12168 - 8P
? 13P = 12168
? P = ? 936
So second part = 1521 - 936 = ? 585
Correct Answer: 44/9%
Explanation:
Given. T1 = 2 yr and T2 = 4 yr,
P1 = 600, P2 = 150.
According to the question,
SI1 + SI2 = 80
[(600 x R x 2)/100] + [(150 x R x 4)/100] = 80
? 120R + 60R = 800
? 180R = 800
? R = 800/180 = 80/18 = 40/9
= 44/9%
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