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- Question
- If a certain sum of money becomes double at simple interest in 12 yr. What would be the rate of interest per annum?
Options- A. 81/3%
- B. 10%
- C. 12%
- D. 14%
- Correct Answer
- 81/3%
ExplanationLet the amount be P, then amount after 12 yr = 2 P
SI = 2P - P = P
SI = (P x R x T)/ 100
P = (P x R x 12)/ 100
? R = 100/12 = 81/3% - 1. Simple interest on ? 1680 for 4 yr at 7 1/ 2 per annum is equal to the simple interest on ? 1200 at 7% per annum for a certain period of time. Time period of time is?
Options- A. 7 yr
- B. 6 yr
- C. 51/3 yr
- D. 71/4 yr Discuss
- 2. What sum of money lent out at simple interest will amount to ? 3400 in 3 yr at 1% per month?
Options- A. ? 2400
- B. ? 1800
- C. ? 1600
- D. ? 2500 Discuss
- 3. If the simple interest for 5 yr be equal to 40% of the principle, it will be equal to the principle after?
Options- A. 12 yr 3 months
- B. 12 yr 6 months
- C. 12 yr 4 months
- D. 12 yr 9 months Discuss
- 4. A man lends Rs. 10000 in four parts. If he gets 8% on Rs. 2000, 7 1/ 2% on Rs . 4000 and 8 1/ 2% on Rs. 1400, What per cent must he get for the remainder if the average interest is 8.13%?
Options- A. 7%
- B. 9%
- C. 91/4%
- D. 101/2 % Discuss
- 5. A sum of Rs. 2540 is lent out into two parts. One at 12% and another one at 12 1/ 2 %. If the total annual income is Rs. 311.60, the money lent at 12% is?
Options- A. Rs. 1180
- B. Rs. 1360
- C. Rs. 1240
- D. Rs. 1340 Discuss
- 6. A sum of ? 4000 is lent out in two parts, one at 8% simple interest and other at 10% simple interest. If the annual interest is ? 352, the sum lent at 8% is
Options- A. ? 1600
- B. ? 2400
- C. ? 1800
- D. ? 2800 Discuss
- 7. A man invests ? 3000 at the rate of 5% per annum. How much more should he invest at the rate of 8%, so that he can earn a total of 6% per annum?
Options- A. ? 1200
- B. ? 1300
- C. ? 1500
- D. ? 2000 Discuss
- 8. When a bank reduce the rate of interest from 6 1/ 2% per annum to 5 1/ 2% per annum, depositor withdrew Rs. 600 and thereby his interest reduced by ? 73. Find the initial deposit.?
Options- A. ? 4000
- B. ? 6000
- C. ? 7000
- D. ? 9000 Discuss
- 9. A farmer borrowed ? 4200 at 10% per annum. At the end of 5 yr he cleared his account by paying ? 5000 and a cow. The cost of the cow is?
Options- A. ? 1300
- B. ? 1240
- C. ? 1200
- D. ? 1340 Discuss
- 10. The simple interest on a sum of money will be ? 600 after 10 yr. It the principle is trebled after 5 yr, what will be the total interest at the end of tenth year?
Options- A. ? 600
- B. ? 900
- C. ? 1200
- D. ? 1500 Discuss
Simple Interest problems
Search Results
Correct Answer: 6 yr
Explanation:
Let the required period of time be T yr.
Then, (1680 x 4 x 15) /100 = (1200 x T x 7)/100
T = (1680 x 2 x 12)/(1200 x 7)
= 6 yr
Hence, the required time period is 6 yr.
Correct Answer: ? 2500
Explanation:
A = ? 3400 T = 3 yr , R = 1% per month = 12 % per annum Let the principle be ? P.
SI = (PTR/100) = (P x 3 x 12)/100 = ? 36P/100
A = (P + SI) = P + 36P/100 = ? 136P/100
? 136P/100 = 3400
? P = (3400 x 100)/136 = 2500
? Sum = ? 2500
Correct Answer: 12 yr 6 months
Explanation:
If interest is 40% of the principal then time = 5 years.
So, when interest would be equal to 100% of the principal time would be
= (100/40) x 5 years = 12.5 years
= 12 yr 6 months
Correct Answer: 9%
Explanation:
? [ (2000 x 8 x 1) /100] + [ (4000 x 15/2 x 1)/100] + [(1400 x 17/2 x 1) / 100] + [(2600 x R x 1)/100] = (10000 x 8.13 x 1) / 100
? 160 + 300 + 119 + 26R = 813
? 26R = 234
? R = 9%
Correct Answer: Rs. 1180
Explanation:
Let money lent at 12% Rs. P
Then, money lent at 121/2% = Rs. (2540 - P )
? (P x 12 x 1)/100 + {(2540 - P) x 25/2 x 1}/100 = 311.60
? 3P/25 + 2540 - P/8 = 311.60
? 24P + 25(2540 - P) = 200 x 311.60
? P = 63500 - 62320 = 1180
Correct Answer: ? 2400
Explanation:
Let the money interest at 8% interest be ? P .
Then, the money interest at 10% interest = ?(4000 - P)
According to the question,
(P x 8 x 1)/100 + [(4000 - P) x 10 x 1]/100 = 352
? 8P + 40000 - 10P = 35200
? 40000 - 35200 = 2P
? P = 4800/2 = ? 2400
Correct Answer: ? 1500
Explanation:
Let the extra money invested = ? P
According to the question .
(3000 x 5 x 1)/100 + (P x 8 x 1)/100 = [(3000 + P) x 6 x 1)]/100
? 15000 + 8P = 18000 + 6P
? 2P = 18000 - 15000
? P = 3000/2 = ? 1500
Correct Answer: ? 4000
Explanation:
Initially ,
let P = ? A, R = 13/2% per annum and T = 1yr
SI = PRT/100 = (A x 1 x 13/2)/100 = ? 13A/200
Now, new deposit = ? (A - 600), R = 11/2 % per annum and T = 1yr
SI = PTR/100 = [(A - 600) x 1 x 11/2)/100] = ? 11(A - 600)/200
By the given condition ,
13A/200 - 11(A - 600)/200 = 73
? 13A - 11(A - 600 ) = 200 x 73
? 2A = 200 x 73 - 600 x 11
? 2A = 14600 - 6600
? 2A = 8000
? A = 4000
Hence, the initial investment is ? 4000.
Correct Answer: ? 1300
Explanation:
Amount after 5 yr, 4200 + (4200 x 10 x 5)/100
= (4200 + 2100) = Rs 6300
? Cost of the cow = (6300 - 5000) = ? 1300
Correct Answer: ? 1200
Explanation:
Let the principle and rate of interest be P and R%
Then, (P x R x 10)/100 = 600
? PR = 6000
Total interest at the end of year = 300 + (3P x R x 5)/100 = 300 + (15 x 6000)/100 = ? 1200
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