? [ (2000 x 8 x 1) /100] + [ (4000 x 15/2 x 1)/100] + [(1400 x 17/2 x 1) / 100] + [(2600 x R x 1)/100] = (10000 x 8.13 x 1) / 100
? 160 + 300 + 119 + 26R = 813
? 26R = 234
? R = 9%
Let money lent at 12% Rs. P
Then, money lent at 121/2% = Rs. (2540 - P )
? (P x 12 x 1)/100 + {(2540 - P) x 25/2 x 1}/100 = 311.60
? 3P/25 + 2540 - P/8 = 311.60
? 24P + 25(2540 - P) = 200 x 311.60
? P = 63500 - 62320 = 1180
Let the sum be Rs. P, SI = Rs. 600, Time = 10 years
? Rate (600 x 100) / (P x 10)%
S.I for first 5 years = Rs. (P x 5 x 6000)/(1000 x P) = Rs. 300
S.I for last 5 years = Rs. (3P x 5 x 6000)/(100 x P) = Rs. 900
Hence, total interest at the end of 10 years = 300 + 900 = Rs. 1200.
Due to the rise in the rate of interest, annual income increases by Rs . (8 - 61/ 2) = Rs , 11/ 2
, when the capital is Rs . 100
Thus, the required capital = (100 x 2 x 4050) / 3 = Rs. 270000
Let each sum be Rs. P.
Then, [(P x 15 x 5) / 100] - [(P x 15 x 7) / 100] x 2 = 144
? 3P/4 -21P/40 = 144
? 9P/40 = 144
? P = (144 x 40) / 9 =Rs. 640
? S.I. for 3/2 years = Rs. (1067.20 - 1012) = Rs. 55.20
? S.I. for 5/2 years = Rs. 55.20 x (2/3) x (5/2) = 92
? Sum = Rs. (1012 - 92) = Rs.920
Hence, Rate = (100 x SI)/(P x T) = (100 x 92) / (920 x 5/2 ) = 4%
If interest is 40% of the principal then time = 5 years.
So, when interest would be equal to 100% of the principal time would be
= (100/40) x 5 years = 12.5 years
= 12 yr 6 months
A = ? 3400 T = 3 yr , R = 1% per month = 12 % per annum Let the principle be ? P.
SI = (PTR/100) = (P x 3 x 12)/100 = ? 36P/100
A = (P + SI) = P + 36P/100 = ? 136P/100
? 136P/100 = 3400
? P = (3400 x 100)/136 = 2500
? Sum = ? 2500
Let the required period of time be T yr.
Then, (1680 x 4 x 15) /100 = (1200 x T x 7)/100
T = (1680 x 2 x 12)/(1200 x 7)
= 6 yr
Hence, the required time period is 6 yr.
Let the amount be P, then amount after 12 yr = 2 P
SI = 2P - P = P
SI = (P x R x T)/ 100
P = (P x R x 12)/ 100
? R = 100/12 = 81/3%
Let the money interest at 8% interest be ? P .
Then, the money interest at 10% interest = ?(4000 - P)
According to the question,
(P x 8 x 1)/100 + [(4000 - P) x 10 x 1]/100 = 352
? 8P + 40000 - 10P = 35200
? 40000 - 35200 = 2P
? P = 4800/2 = ? 2400
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