S.I for 3 years = Rs. (1350 - 1260) = Rs. 90
S.I for 2 years = Rs.(90/3) x 2 = Rs . 60
? Sum = Rs. (1260 - 60) = Rs. 1200
? Rate = (100 x SI) / (P x T) = (100 x 60) / (1200 x 2) = 2.5%
Let the capital be Rs. P, then
(P/3) x (7/ 100) + (x/4) x (8/100) + [P - (P/3 + P/4)] x 10/100 = 561
? 7P/300 + P/50 + P/24 = 561
? 42P + 36P + 75P = 1009800
P = 1009800/153 = 6600
Let capital = Rs . P
Then, SI1 - SI2 = 104.
? (P x 13 x 1)/100 - (P x 25/2 x 1) /100 = 104
? 13P/100 - P/8 = 104
? 26P -25P = (104 x 200)
? P = 20800
? Capital = Rs. 20800
Let principle = Rs. P
Then S.I = P/9
Let Rate = R% per annum and time = R years
Then, as we know SI = (P x R x T) / 100.
? P/9 = ( P x R x R) / 100
? R2 = 100/9
? R = 10/3 = 31/3 % per annum
Let the sum be Rs 'y' and , rate of interest = R%
Simple Interest for 2 yr =Rs( 625 - 575 ) = Rs 50
? Sum of money, y=Rs( 575 - 75)= Rs 500
? R= [(100 x SI)/(Sum x Time)]
=[(100x 75)/(500 x 3)]=5 %
As Sum = [(100 x SI)/(Time x Rate)]
here, let R =x%, T=x yr, and, SI=Rs x
? Sum=[(100 × x)/(x × x)]
=(100/x)
Let rate = R% per annum.
Then, [(600 x R x 2)/ 100 ] + [(150 x R x 4 ) / 100] = 90
? 18R = 90
? R = 5%
Principal = Rs. 800
S.I. = Rs. (920 - 800) = Rs. 120
and Time = 3 years
? Original rate = (100 x SI) / (P x T) = (100 x 120) / ( 800 x 3) = 5%
New rate = 8%
Now, S.I . = Rs.(800 x 8 x 3) /100 = Rs. 192
? Amount = Rs. (800 + 192)
= Rs. 992
Let, Sum = P
Then S.I = P/2
Rate = 8%
and Time = 6 years
But P/2 = (P x 8 x 6) /100 (Not possible )
Thus, data is inadequate.
Let rate = R% per annum. Then,
(1200 x R x 3)/100 - (1000 x R x 3)/100 = 50
? 6R = 50
? R = 81/3
? Rate = 81/3% per annum
Let principal = P.
Then, S.I = P,
Rate (R) = 12%
Time = (100 x SI) / (R x P) = (100 x P) / (P x 12) years
= 25/3 years
= 8 years 4 months
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