Let the sum be P.
And the original rate be y% per annum.
Then new rate=(y+3)% per annum
According to question, [(P × (y+3) × 2)/100]=[(P × y × 2)/100]=300
? [(Py + 3P)/100]=[Py/100] = 150
? Py+ 3P - Py=15000
? 3P=15000
? P= 5000
Thus, the sum is Rs 5000
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
Subtract 20, 25, 30, 35, 40, 45 from successive numbers. So 0 is wrong.
NA
Each previous number is multiplied by 2.
? 8 m shadow means original height = 12 m
? 1 m shadow means original height = 12/8 m
? 100 m shadow means original height = (12/8) x 100 m
= (6/4) x 100 = 6 x 25 = 150 m
Let 8% of 96 = y of 1/25
? (8 x 96)/100 = y/25
? y = (8 x 96 x 25)/100 = 192
Since the principal is not given, so data is inadequate.
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