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- Question
- The simple interest on a sum of money at 8% per annum for 6 yr is half the sum. What is the sum?
Options- A. ? 4800
- B. ? 6000
- C. ? 8000
- D. Data is inadequate
- Correct Answer
- Data is inadequate
ExplanationLet sum = P
Then, according to the question.
SI = P/2
? P/2 = (P x 8 x 6)/100
? It is clear that data is inadequate. - 1. The simple interest on a sum of money at 9% per annum for 5 yr is half the sum. What is the sum?
Options- A. ? 5800
- B. ? 5000
- C. ? 7000
- D. Data is inadequate Discuss
- 2. A sum of money amounts to ? 2240 at 4% per annum simple interest in 3 yr. The interest on the same sum for 6 months at 3.5% per annum is
Options- A. ? 30
- B. ? 50
- C. ? 35
- D. ? 150 Discuss
- 3. The simple interest on ? 4000 in 3 yr at the rate of R % per annum equals equals to the simple interest on ? 5000 at the rate of 12% per annum in 2 yr The value of R is
Options- A. 6%
- B. 8%
- C. 9%
- D. 10% Discuss
- 4. Mr. Deepak invested an amount of ? 21250 for 6 yr. At what rate of simple interest, will he obtain the total amount of ? 26350 at the end of 6 yr?
Options- A. 6% pa
- B. 5% pa
- C. 8% pa
- D. 12% pa Discuss
- 5. At what rate per annum will the simple interest on a certain sum of money be 1/5 of the amount in 10 yr?
Options- A. 5%
- B. 2%
- C. 1%
- D. 8% Discuss
- 6. A sum was put at simple interest at a certain rate for 2 years . Had it been put at 3% higher rate, it would have fetched Rs 300 more. The sum is
Options- A. Rs 5000
- B. Rs 6000
- C. RS 7000
- D. None Of these Discuss
- 7. The simple interest on a sum of money at 10% per annum for 6 year is half the sum. Then, the sum is?
Options- A. Rs 5000
- B. Not possible
- C. Rs 4000
- D. Rs 6000 Discuss
- 8. The simple interest at x% for x years will be Rs x on a sum of ....
Options- A. Rs x
- B. Rs 100x
- C. Rs (100/x)
- D. Rs (100/ x2) Discuss
- 9. A certain sum lent out at simple interest amounts to Rs 575 in 3 yr and to Rs 625 in 5 yr. Then the rate of interest is?
Options- A. 3%
- B. 4%
- C. 5%
- D. 7% Discuss
- 10. The simple interest on a sum of money is 1/9 of the principle and the number of years is equal to the rate percent annum. The rate percent annum is?
Options- A. 3
- B. 1/3
- C. 31/3
- D. 3/10 Discuss
Simple Interest problems
Search Results
Correct Answer: Data is inadequate
Explanation:
Let the sum be P.
? SI = P/2
? P/2 = (P x 9 x 5)/100
Clearly data is inadequate.
Correct Answer: ? 35
Explanation:
If the sum be ? P, then
(2240 - P) = (P x 4 x 3)/100
? 2240 = 12P/100 + P
? 2240 = 112P/100
? P = (2240 x 100)/112 = ? 2000
Now, required interest,
SI = PRT/100 = [{2000 x (7/2) x (1/2)} /100]
= ? 35
Correct Answer: 10%
Explanation:
Since, the two simple interest are equal.
Then, (4000 x 3 x R)/100 = (5000 x 12 x 2)/100
? R = 10%
Correct Answer:
Explanation:
SI = 26350 - 21250 = ? 5100
? Rate = (SI x 100) / (Principal x Time)
= (5100 x 100) / (21250 x 6)
= 4%
Correct Answer: 2%
Explanation:
Let sum = P, then SI = P/5 time = 10 yr.
? Rate = (100 x P)/(P x 5 x 10) = 2%
Correct Answer: Rs 5000
Explanation:
Let the sum be P.
And the original rate be y% per annum.
Then new rate=(y+3)% per annum
According to question, [(P × (y+3) × 2)/100]=[(P × y × 2)/100]=300
? [(Py + 3P)/100]=[Py/100] = 150
? Py+ 3P - Py=15000
? 3P=15000
? P= 5000
Thus, the sum is Rs 5000
Correct Answer: Not possible
Explanation:
Let the sum be Rs 'y'
Since Simple Interest = Rs ( y / 2)
and, T = 6 yr , R = 10% per annum
So Simple Interest, SI = (P x R x T)/100
where, R = Rate
T = Time
SI= Simple Interest
now, According to problem, ( y / 2 ) = ( y x 10 x 6)/100
? (1/2)=(6/10)
? which is not true, so it is not a possible case.
Correct Answer: Rs (100/x)
Explanation:
As Sum = [(100 x SI)/(Time x Rate)]
here, let R =x%, T=x yr, and, SI=Rs x
? Sum=[(100 × x)/(x × x)]
=(100/x)
Correct Answer: 4%
Explanation:
Let the sum be Rs 'y' and , rate of interest = R%
Simple Interest for 2 yr =Rs( 625 - 575 ) = Rs 50
? Sum of money, y=Rs( 575 - 75)= Rs 500
? R= [(100 x SI)/(Sum x Time)]
=[(100x 75)/(500 x 3)]=5 %
Correct Answer: 31/3
Explanation:
Let principle = Rs. P
Then S.I = P/9
Let Rate = R% per annum and time = R years
Then, as we know SI = (P x R x T) / 100.
? P/9 = ( P x R x R) / 100
? R2 = 100/9
? R = 10/3 = 31/3 % per annum
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