Here, P = ? 2668, T = 5 yr, A = ? 4669
We know that,
Amount (A) = Principal (P) + (Simple Interest) SI
4669 = 2668 + SI
? SI = 4669 - 2668 = ? 2001
Again, SI = (P x R x T)/100
? 2001 = (2668 x R x 5)/100
? R= (2001 x 100) / (2668 x 5)
= (2001 x 5)/667
= 15%
Given, t = 8 yr, r = 3.5%, A = ? 364.80
Let amount = ? P
Since, A =P [1 + (RT/100)]
? 364.80 = P[1 + (3.5 x 8)/100]
? 364.80 = P[ 1+ (35 x 8)/100]
? 3648/10 = P x (128/100)
? P = 3648/128
= ? 285
Let sum = P
Then, SI = (P x R x T)/100
= {P x (27/2) x 4} / 100
= {P x 54} / 100 = 27P / 50
? Amount = P + 27P / 50 = 77P/50
According to the question 77P/50 = 3080
? P = (3080 x 50)/77 = ? 2000
Here, P = ? 25800, R = 14%
T = 1 yr 4 months = 1 + (4/12) years = 1 + (1/3) = 4/3 yr.
According to the formula,
SI = (P x R x T) / 100 = {25800 x 14 x (4/3)}/100
= (258 x 14 x 4)/3
= ? 4816
Given, P = ? 8750., R = 7% T = 3 yr
According to the formula.
SI = (P x R x T)/100 = (8750 x 7 x 3)/100
= ? 1837.50
Here, P = ? 4000, R = 121/2% = 25 / 2%
T = (24 + 31 + 18) days = 73 days
= 73/365 yr = 1/5 yr
? SI = (P x R x T)/100 = (4000 x 25/2 x 1/5 )/100
= ? 100
The required difference in amount and principal is SI = A - P
Here, P = ? 4000, R = 5% T = 4 yr
According to the formula.
SI = (P x R x T) /100
= (4000 x 5 x 4)/100
= ? 800
Here, n = 2, T = 10 yr
? R = 100 (n - 1)/T
= 100(2 - 1)/10
= 100/10
= 10%
Let sum be P.
? 50% of P = P/2 = SI
Now, P/2 = (P x 5 x T) / 100 [ as time = 10 yr]
? P/2 = 5PT / 100
? 1/2 = T/20
? = T = 10 yr
Let sum = p
Then, after 15 yr
Sum = 8p
? SI = 8p - P = 7P
Now, 7P = (P x R x 15)/100
? 7 = 15R/100 = 3R/20
? R = (20 x 7)/3 = 140/3
= 462/3%
Given, T1 = 21/2 yr, T2 = 4 Yr
According to the question.
[P + (P x R x 4)/100] - [P + (P x R x 2.5)/100] = 1067.20 - 1012 = 55.2
? (1.5 x P x R)/100 = 55.2
? PR = (552 x 100) / 15 = 3680
For 4 yr.
SI = PRT/100 = (3680 x 4)/100 = ? 147.2
? Sum (P) = 1067.2 - 147.2 = ? 920
We have, PR = 3680
? R = 3680/P = 3680/920 = 4%
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