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- Question
- The sum which amount to ? 364.80 in 8 yr at 3.5% simple interest per annum is
Options- A. ? 285
- B. ? 280
- C. ? 275
- D. ? 270
- Correct Answer
- ? 285
ExplanationGiven, t = 8 yr, r = 3.5%, A = ? 364.80
Let amount = ? P
Since, A =P [1 + (RT/100)]
? 364.80 = P[1 + (3.5 x 8)/100]
? 364.80 = P[ 1+ (35 x 8)/100]
? 3648/10 = P x (128/100)
? P = 3648/128
= ? 285 - 1. A sum at simple interest of 13 1/ 2% per annum amounts to ? 3080 in 4 yr Find the sum.
Options- A. ? 1550
- B. ? 1680
- C. ? 2000
- D. ? 1850 Discuss
- 2. What will be simple interest for 1 yr and 4 months on a sum of ? 25800 at the rate of 14% per annum?
Options- A. ? 4816
- B. ? 2580
- C. ? 4816.75
- D. ? 4815 Discuss
- 3. Rakesh lent out ? 8750 at 7% annual interest, Find the simple interest in 3 yr.
Options- A. ? 1870
- B. ? 1837.50
- C. ? 1560
- D. ? 2200 Discuss
- 4. What will be the simple interest on ? 4000 at 12 1/ 2% per annum for the period from 4th February, 2005 to 18th April, 2005?
Options- A. ? 215
- B. ? 120
- C. ? 200
- D. ? 100 Discuss
- 5. What would be the simple interest accrued in 4 yr on a principle of ? 18440 at the rate 15% per annum?
Options- A. ? 11075
- B. ? 12250
- C. ? 11500
- D. ? 12985 Discuss
- 6. A sum of ? 2668 amount to ? 4669 in 5 yr at the rate of simple interest . Find the rate per cent.
Options- A. 15.2%
- B. 14.9%
- C. 16%
- D. 15% Discuss
- 7. Find the difference in amount and principal for ? 4000 at the rate of 5% annual interest in 4 yr.
Options- A. ? 865.50
- B. ? 865
- C. ? 400
- D. ? 800 Discuss
- 8. A sum becomes its double in 10 yr. Find the annual rate of simple interest.
Options- A. 1%
- B. 5%
- C. 10%
- D. 20% Discuss
- 9. How long will a sum of money invested at 5% per annum SI take to increase its value by 50%
Options- A. 10 yr
- B. 12 yr
- C. 15 yr
- D. 7 yr Discuss
- 10. A certain sum becomes 8 fold in 15 yr at simple interest. What will be the rate interest?
Options- A. 465/3%
- B. 462/3%
- C. 465/8%
- D. 4612/11% Discuss
Simple Interest problems
Search Results
Correct Answer: ? 2000
Explanation:
Let sum = P
Then, SI = (P x R x T)/100
= {P x (27/2) x 4} / 100
= {P x 54} / 100 = 27P / 50
? Amount = P + 27P / 50 = 77P/50
According to the question 77P/50 = 3080
? P = (3080 x 50)/77 = ? 2000
Correct Answer: ? 4816
Explanation:
Here, P = ? 25800, R = 14%
T = 1 yr 4 months = 1 + (4/12) years = 1 + (1/3) = 4/3 yr.
According to the formula,
SI = (P x R x T) / 100 = {25800 x 14 x (4/3)}/100
= (258 x 14 x 4)/3
= ? 4816
Correct Answer: ? 1837.50
Explanation:
Given, P = ? 8750., R = 7% T = 3 yr
According to the formula.
SI = (P x R x T)/100 = (8750 x 7 x 3)/100
= ? 1837.50
Correct Answer: ? 100
Explanation:
Here, P = ? 4000, R = 121/2% = 25 / 2%
T = (24 + 31 + 18) days = 73 days
= 73/365 yr = 1/5 yr
? SI = (P x R x T)/100 = (4000 x 25/2 x 1/5 )/100
= ? 100
Correct Answer:
Explanation:
Given, P = 18440, R = 15%, T = 4
? Simple interest (SI) = (P x R x T) / 100
= (4 x 18440 x 15) / 100
= ? 11064
Correct Answer: 15%
Explanation:
Here, P = ? 2668, T = 5 yr, A = ? 4669
We know that,
Amount (A) = Principal (P) + (Simple Interest) SI
4669 = 2668 + SI
? SI = 4669 - 2668 = ? 2001
Again, SI = (P x R x T)/100
? 2001 = (2668 x R x 5)/100
? R= (2001 x 100) / (2668 x 5)
= (2001 x 5)/667
= 15%
Correct Answer: ? 800
Explanation:
The required difference in amount and principal is SI = A - P
Here, P = ? 4000, R = 5% T = 4 yr
According to the formula.
SI = (P x R x T) /100
= (4000 x 5 x 4)/100
= ? 800
Correct Answer: 10%
Explanation:
Here, n = 2, T = 10 yr
? R = 100 (n - 1)/T
= 100(2 - 1)/10
= 100/10
= 10%
Correct Answer: 10 yr
Explanation:
Let sum be P.
? 50% of P = P/2 = SI
Now, P/2 = (P x 5 x T) / 100 [ as time = 10 yr]
? P/2 = 5PT / 100
? 1/2 = T/20
? = T = 10 yr
Correct Answer: 462/3%
Explanation:
Let sum = p
Then, after 15 yr
Sum = 8p
? SI = 8p - P = 7P
Now, 7P = (P x R x 15)/100
? 7 = 15R/100 = 3R/20
? R = (20 x 7)/3 = 140/3
= 462/3%
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