Let principal = P
Then, SI = 2P & Time = 15 years
? Required rate = (100 x SI) / (P x T) = (100 x 2P) / (P x 15) = 200/15 = 131/3 per annum
S.I for 1 year = Rs. (925 - 850) = Rs. 75
S.I for 3 year = Rs. (75 x 3) = Rs. 225
? Sum = Rs. (850 - 225) = Rs. 625
S.I on Rs. 64 for 2 year = Rs. 19.20
? Rate = (100 x SI) / (P x T) = (100 x 19.20) / (64 x 2) = 15%
? S.I On Rs. 86 for 4 year = (P x R x T) / 100 = Rs. (86 x 4 x 15 ) /100 = Rs.51.60
? Amount of Rs. 86 after 4 years = Rs. (86 + 51.60) = Rs. 137.60
S.I. for 1 year = Rs. (783 - 702) = Rs 81
S.I. for 2 years = Rs. (81 x 2) = Rs. 162
? Sum = Rs. (702 - 162) = Rs. 540
? Required rate = = (100 x SI) / (P x T) = (100 x 162) / (540 x 2) % = 15%
Required sum = Rs. (100 x SI ) / ( T x R )
= (100 x 235.20) / (3 x 14)
= Rs. 560
Rate of Interest = 12% per annum
Simple Interest =Rs 6000 per annum
Let 'P' is the principal
SI= (P x R x T)/100
where , SI= Simple Interest
T= Time
R= Rate
? 6000=(P x 1 x 12)/100
? P =(6000 x 100)/12
= Rs 50000
Hence the required amount is Rs 50000
Let principal = P. Then, S. I = P. and Time = 10 years
? Required time = [(n - 1) x t] / (m - 1)
= [(3 - 1) x 10] / (2 - 1)
= 20 years
S.I for 3 years = Rs. (2600 - 2240) = Rs . 360
S.I for 2 years = Rs. (360/3 x 2) = Rs. 240
? Required sum = Rs . (2240 - 240) = Rs. 2000
Sum = (100 x SI) / (R x T)
= (100 x R) / (R x R)
= Rs. 100/R
Let sum = P, then SI = P and Time = 20 years
? Required rate = (100 x SI)/(P x T) = (100 x P) / (P x 20) = 5% per annum
Let the annual installment be Rs. P
Then, [P + (P x 4 x 8)/100] + [P + (P x 3 x 8) / 100] + [P + (P x 2 x 8)/100 ] + [ P + (P x 1 x 8)/100] + P = 580
? 33P/25 + 31P/25 + 29P/25 + 27P/25 + P = 580
? (120 + 25)P = 580 x 25
? P = 100
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