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- Question
- A sum of money at simple interest amount to Rs 1260 in 2 yr and Rs 1350 in 5 yr, then the rate percent per annum is?
Options- A. 30%
- B. 10%
- C. 2.5%
- D. 5%
- Correct Answer
- 2.5%
ExplanationSimple in 3 year = Rs( 1350 - 1260) = Rs 90
Simple in 2 year = (2/3) &time; 90= Rs 60
Principal = Rs (1260 -60)= Rs 1200
Rate, R= (100 x SI)/(P x T)= (100 x 60)/(1200 x 2)=60/24= 25 %
where , SI= Simple Interest
P= Principal
T= Time - 1. If a certain sum is doubled in 8 yr on simple interest, in how many year will it be four times?
Options- A. 24 yr
- B. 16 yr
- C. 32 yr
- D. 12 yr Discuss
- 2. Find the sum of money will amount to Rs 900 in 4 years at 5 % per annum on simple interest?
Options- A. Rs 750
- B. Rs 650
- C. Rs 500
- D. Rs 550 Discuss
- 3. A certain sum amounts to Rs 1586 in 2 year and Rs 1729 in 3 year. Find the rate and the sum.
Options- A. 8 %
- B. 9 %
- C. 10 %
- D. 11 % Discuss
- 4. The amount instalment will discharge on debit of Rs 3220 due in 4 year at 10 % simple interest?
Options- A. 500
- B. 600
- C. 700
- D. None of these Discuss
- 5. At what rate percent per annum will a sum of money double in 8 yr?
Options- A. 12 %
- B. 12.5 %
- C. 13 %
- D. 15 % Discuss
- 6. The difference of 13% per annum and 12% of a sum in 1 year is Rs 110.Then the sum is?
Options- A. Rs 12000
- B. Rs 13000
- C. Rs 11000
- D. Rs 16000 Discuss
- 7. At what rate percent per annum simple interest , will a sum of money triple itself in 25 year?
Options- A. 8%
- B. 5%
- C. 6%
- D. 12 % Discuss
- 8. A certain sum at simple interest amounts to Rs 1040 in 3 Yr and to Rs 1360 in 7 yr.Then the sum is?
Options- A. Rs 750
- B. Rs 800
- C. Rs 900
- D. Rs 1000 Discuss
- 9. If the rate of simple interest is 12% per annum the amount that would fetch interest of Rs 6000 per annum is?
Options- A. Rs 7200
- B. Rs 72000
- C. Rs 50000
- D. Rs 48543.69 Discuss
- 10. The simple interest on a certain sum for 3 years at 14% per annum is Rs. 235.20. The sum is?
Options- A. Rs. 480
- B. Rs. 560
- C. Rs. 650
- D. Rs. 720 Discuss
Simple Interest problems
Search Results
Correct Answer: 24 yr
Explanation:
Let the sum be Rs 'y' , so amount = 2y
Simple interest =Rs y
Let R be the rate of interest,
R= (100 x SI)/(P x T) = (100 x y) / (y x 8) = 12.5 %
where SI= Simple Interest
P = Principal
T = Time
now, the needed amount = Rs 4y
since SI = Rs (4x-x)= Rs 3y
since T= (100 x SI)/(P x R)
= (100 x 3y )/(y x 125)= 24 yr
Correct Answer: Rs 750
Explanation:
Let the sum of money be Rs y
So Amount = y +[( y x 5 x 4 )/100]
But Amount = Rs 900
? 900 = y +(20y)/100
? 900 = 6y / 5
? y = ( 900 x 5) /6
= Rs 750
Correct Answer: 11 %
Explanation:
Simple Interest in 1 year= Rs (1729 - 1586)
= Rs 143
now, SI in 2 year = Rs 286
Principal P= Rs(1586 - 286)
= 1300
And R= (100 × SI)/(P × T)
= (100 × 143)/(1300 × 1)
= 11 %
where, R = rate
SI= Simple Interest
P = Principal
T= Time
Correct Answer: 700
Explanation:
Let the amount instalment be Rs ' x '
Then According to question,
(Amount of 'x' for 3 yrs) + (Amount of 'x' for 2 yrs) + (Amount of 'x' for 1 yrs) + x =3220
or, [x+(x × 10 × 3)/100] + [x+(x × 10 × 2)/100] + [x+(x × 10 × 1)/100] + x=3220
? 4x+ (30x/100)+(20x/100)+(10x/100)=3220
? 460x=322000
? x=Rs 700
? Each Instalment= Rs 700
Correct Answer: 12.5 %
Explanation:
Let Sum = P, Then SI=P
As Amount A = 2 × P
where , P = Principal
Rate R = (100 × SI)/(P × T)
= (100 × P)/(P × 8) %
= 12.5 %
where , SI= Simple Interest
T= Time
Correct Answer: Rs 11000
Explanation:
Let the sum be 'y'
then, [(y x13 x 1)/100 ]- [( y x 12 x 1) / 100]=110
since ( y / 100 ) = Rs 110
? Y = Rs 11000
Correct Answer: 8%
Explanation:
Let principal amount = P
As amount =3P, T=25 yr
? SI=3P-P=2P
? Rate R = (100 x SI)/(P x T)
where, SI= Simple Interest T = Time
= (100 x 2P)/(P x 25)=8%
Correct Answer: Rs 800
Explanation:
Simple Interest for 4 yr = Rs(1360 - 1040 ) = Rs 320
so, Simple Interest for 3 yr= Rs [(320/4) x 3]= Rs 240
Sum = Rs (1040-240)= Rs 800
Correct Answer: Rs 50000
Explanation:
Rate of Interest = 12% per annum
Simple Interest =Rs 6000 per annum
Let 'P' is the principal
SI= (P x R x T)/100
where , SI= Simple Interest
T= Time
R= Rate
? 6000=(P x 1 x 12)/100
? P =(6000 x 100)/12
= Rs 50000
Hence the required amount is Rs 50000
Correct Answer: Rs. 560
Explanation:
Required sum = Rs. (100 x SI ) / ( T x R )
= (100 x 235.20) / (3 x 14)
= Rs. 560
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