More Questions from Problems on Numbers

Find the number such that when it is multiplied by 15, the result is greater than the original number by 56.

Aptitude Problems on Numbers Difficulty: Easy
Choose an option
  • A
    6
  • B
    4
  • C
    3
  • D
    12

Answer

Correct Answer: 4

Explanation

Introduction / Context: This question is a simple algebraic equation problem involving an unknown number and a relationship between its multiple and itself. The statement describes how much bigger the product of the number and 15 is compared to the original number. From this, we can form a linear equation and solve for the unknown. Such questions are meant to test basic equation setup skills in aptitude exams.

Given Data / Assumptions:

  • Let the unknown number be x.
  • When x is multiplied by 15, the result is 56 more than x.
  • We need to determine the value of x.

Concept / Approach: The phrase "when it is multiplied by 15, the result is 56 greater than the original number" can be expressed algebraically as 15x = x + 56. This is a simple one-variable linear equation. Solving this equation will give the value of x directly. Once x is found, we check whether it matches one of the options and whether it satisfies the original condition stated in the problem.

Step-by-Step Solution: Step 1: Let the required number be x. Step 2: According to the problem, when x is multiplied by 15, we get a value that is 56 more than x. Step 3: Translate this into an equation: 15x = x + 56. Step 4: Subtract x from both sides to gather like terms: 15x − x = 56. Step 5: This simplifies to 14x = 56. Step 6: Divide both sides by 14: x = 56 / 14. Step 7: Compute the division: 56 / 14 = 4. Step 8: Therefore, the required number is 4.

Verification / Alternative check: Check the condition with x = 4. The product when multiplied by 15 is 15 * 4 = 60. The original number is 4. The difference 60 − 4 = 56, which matches the statement that the product is 56 greater than the original number. This confirms that x = 4 is correct.

Why Other Options Are Wrong: Option (a) 6: If x = 6, then 15x = 90 and 90 − 6 = 84, not 56. Option (c) 3: If x = 3, then 15x = 45 and 45 − 3 = 42, not 56. Option (d) 12: If x = 12, then 15x = 180 and 180 − 12 = 168, not 56.

Common Pitfalls: Some learners misinterpret the phrase and write 15x + 56 = x or x = 15x + 56, which reverses or distorts the relationship. Others may make arithmetic errors when subtracting x from 15x. Carefully translating the wording into a correct equation and handling the subtraction correctly avoids these mistakes.

Final Answer: The required number is 4.

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