Difficulty: Medium
Correct Answer: 4 : 9
Explanation:
Introduction:
This problem tests alligation using milk fractions (concentrations). We first convert each vessel's ratio into milk fraction, then find how to mix a higher milk fraction with a lower milk fraction to achieve exactly 50% milk.
Given Data / Assumptions:
Concept / Approach:
Convert ratios to milk fractions:\nMilk fraction = milk / (milk + water).\nThen apply alligation with fractions:\nRatio (higher : lower) = (target - lower) : (higher - target).
Step-by-Step Solution:
Vessel 1 milk fraction = 3 / (3 + 1) = 3/4Vessel 2 milk fraction = 7 / (7 + 11) = 7/18Target milk fraction = 1/2Compute (target - lower) = 1/2 - 7/18 = (9/18 - 7/18) = 2/18 = 1/9Compute (higher - target) = 3/4 - 1/2 = 1/4Required ratio (Vessel 1 : Vessel 2) = (target - lower) : (higher - target) = (1/9) : (1/4)Convert ratio: (1/9) : (1/4) = 4 : 9
Verification / Alternative Check:
Take 4 parts from vessel 1 and 9 parts from vessel 2.\nMilk amount proportional = 4*(3/4) + 9*(7/18) = 3 + 3.5 = 6.5 parts.\nTotal parts = 4 + 9 = 13.\nMilk fraction = 6.5/13 = 0.5 = 50%, correct.
Why Other Options Are Wrong:
1:1 or 4:7: does not balance the milk fraction to exactly 1/2.5:7: gives milk fraction higher than 1/2 because vessel 1 is very rich in milk.9:4: reversed ratio, would push milk fraction above 50%.
Common Pitfalls:
Using milk:water ratios directly in alligation without converting to milk fractions.Mixing up which vessel is higher and which is lower in milk content.Forgetting that 50% milk means milk fraction = 1/2 exactly.
Final Answer:
4 : 9
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