Nandita scores 80% marks in five subjects together, viz., Hindi, Science, Mathematics, English and Sanskrit, where in the maximum marks of each subject were 105, How many marks did Nandita score in Science, if she scored 89 marks in Hindi, 92 marks in Sanskrit, 98 marks in Mathematics and 81 marks in English?

Couldn't be determined, since the total amount of money is not given in either of the case

A +10 = 3(B - 10)
? A - 3B = -20 ....(i)
And ( A - 10) = (B + 10)
? A - B = 20 ...(ii)

on subtracting Eq.(ii) from Eq.(i), we get
(A - 3B) - (A - B) = -20 - 20
? - 2B = - 40
there4; B = 20

Now, by using Eq. ...(ii),
there4; Ratio of the numbers of students of A and B = 40 : 20 = 2 : 1

Ratio of the amounts collected from 1st and 2nd classes fairs = (3 x 1) ; (1 x 50) = 3 : 50
? Amount collected from 2nd class
Passengers = 2650 x (50/53) = ? 2500

Let B gets x.
Then, A gets (x + 40) and C gets (x + 70).
According to the question,
x + 40 + x + x + 70 = 710
? 3x = 710 - 110 = 600
? x = 600/3 = 200
? C's share = 200 + 70 = ? 270

Accoridng to rhe question
A = ( B + C)/2
? B + C = 2A
? A + B + C = 3A (adding A on both sides)
? 3A = 5625
? A = 5625/3 = ? 1875 ....(i)

Again from question B = (A + C)/4
? A + C = 4B
? A + B + C = 5B (adding B on both sides)
? 5B = 5625
? B = 5624/5 = ? 1125 ...(ii)

From (i) and (ii)
? A + B = 1875 + 1125 = ? 3000

Let total number of employees in beginning = 8K and total number of employees in present = 7K
Let salary of an employee in beginning = 5L and salary of an employee in present = 6L
? Total salary in beginning = 8K x 5L = 40KL
and total salary in present = 7K x 6L = 42 KL
Required ratio = 40KL : 42KL = 20 : 21
Clearly, salary is increased.

Since there are 70 males out of 120 applicants, there must be 50 females out must have For the minimum number of males to have a driver's licence all 50 females must have a driver's license Thus the number of males having a driver's licence will be 80 - 50 = 30. The maximum possible number of males having a driver's license is 70. The ratio between the minimum and the maximum is 30 : 70 or 3 : 7 .

Quantity of acid in the mixture = (2/3) x 60 = 40 L
Quantity of water in the mixture = (1/3) x 60= 20 L
Let the required quantity of water be x L.
According to the question,
40/(20+ x) = 1/2
? 80 = 20 + x
? x = 60 L

Let the cost of third variety tea will be ? N per kg
According to the question,
(126 + 135 + 2N)/4 = 153
? (261 + 2N) = 4 x 153
? 2N = 612 - 261 = 351
? N = 351/2 = 175.50
? N = ? 175.5
Hence, the cost of third variety tea is ? 175.50 per kg .

Required compound ratio = (2 x 5 x 4) / (7 x 3 x 7)
= 40/147
= 40 : 147