Identity with mutual percentages:\nShow that (A% of B + B% of A) is equal to which of the following?

Difficulty: Easy

Correct Answer: 2% of AB

Explanation:


Introduction / Context:
This question checks comfort with symbolic percentages and distributive reasoning. Recognizing symmetrical expressions helps in algebraic simplification.


Given Data / Assumptions:

  • We interpret A% of B as (A/100) * B, and B% of A as (B/100) * A.
  • We need the simplified sum in familiar percentage form.


Concept / Approach:
Write both terms explicitly and factor common pieces. Because multiplication is commutative, A * B and B * A are the same. Combine like terms to reach a compact result.


Step-by-Step Solution:

A% of B = (A/100) * B.B% of A = (B/100) * A.Sum = (A/100)B + (B/100)A = (AB/100) + (AB/100) = 2AB/100.Thus, the sum equals 2% of AB.


Verification / Alternative check:
Use numbers: Let A = 10 and B = 50. Then A% of B = 10% of 50 = 5; B% of A = 50% of 10 = 5; total = 10. Meanwhile, 2% of AB = 2% of 500 = 10 — matches.


Why Other Options Are Wrong:

  • A% of B or B% of A alone accounts for only half the sum.
  • “AB% of 3” is not a meaningful standard expression.
  • A% of A + B% of B is unrelated to the symmetric cross terms here.


Common Pitfalls:
Confusing “A% of B + B% of A” with “(A+B)% of (A+B)”. Keep symbols aligned with their operands.


Final Answer:
2% of AB

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