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As per the given above question , we have
Let k1 and k2 be the roots of quadratic equation .
One root is k1 = ?5
So the other root is k2 = ? ?5
? Sum of the roots = k1 + k2 = ?5 + ( -?5 ) = 0
and product of the roots = k1 × k2 = ? (?5) (- ?5) = ?5
? Required equation is x2 - (sum of the roots)x + (product of the roots) = 0
? x2 - 5 = 0.
Let Mr . Arjun is on tour for N days.
Then, according to the question,
Difference in expenses per day for original and extended tour = 3
360/N - 360/(N + 4) = 3
? 1/N - 1/(N + 4) = 3/360 = 1/120
? [N + 4 - N] / [ N x (N + 4)] = 1/120
? N(N + 4) = 4 x 120 = 480
? N2 + 4N - 480 = 0
? N2 + 24 - 20x - 480 = 0
? N(N + 24) - 20(N + 24) = 0
? (N + 24) (N - 20) = 0
? N = 20
(we ignore -ve value of x, that is, -24 because days cannot be negative)
4/?x + 7/?x = ?x;
? 11/?x = ?x
? x = 11
and y2 - (11)5/2/?y = 0
? y2 = (11)5/2/(y)1/2
? y2 x y1/2 = (11)5/2
? (y)5/2 = (11)5/2
? y = 11
? x = y
x2 - 365 = 364
? x2 = 364 + 365
? x = ?729 = ± 27
and y - ?324 = ?81 ? y - 18 = 9
? y = 27
So, y ? x or x ? y because y = 27 and x = 27 and - 27.
3x2 + 8x + 4 = 0
? 3x2 + 6x + 2x + 4 = 0
? 3x(x + 2) + 2(x + 2) = 0
? (x + 2) (3x + 2) = 0
? x = - 2, - 2/3
and 4y2 - 19y + 12 = 0
? 4y2 - 16y - 3y + 12 = 0
? 4y(y - 4) -3(y - 4) = 0
? (y - 4) (4y - 3) = 0
? y = 4, 3/4
Hence, y > x or x < y
According to question ,we can say that
From equation ?. x2 ? 19x + 84 = 0
? x2 ? 7x ? 12x + 84 = 0
? (x ? 7)(x ? 12) = 0
? x = 7, 12
From equation ?. y2 ? 25y + 156 = 0
? y2 ? 13y ? 12y + 156 = 0
? (y ? 13)(y ? 12) = 0
? y =12, 13
? x ? y
From above it is clear that x ? y is correct answer .
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According to question ,we can say that
From equation ?. ?784x + 1234 = 1486
? ?784x = 252
? 28x = 252
? x = 9
From equation ?. ?1089y + 2081 = 2345
? ?1089y = 264
? 33y = 264
? y = 8
? x > y
Thus , required answer will be x > y .
According to question,
From equation ?. x3 ? 468 = 1729
? x3 = 2197 = 133
? x = 13
From equation ?. y2 ? 1733 + 1564 = 0
? y2 = 169 = 132
? y = ±13
Thus , x ? y is required answer .
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