Unit digit in 34 = 1
? Unit digit in ( 34 )16 = 1
? Unit digit in 365 = 3
Unit digit in 659 = 6
Unit digit in 771 = 3
? Required unit digit = Unit digit in ( 3 x 6 x 3 )
= Unit digit in 54
= 4
Required unique digit = Unique digit in (7)754
= Unique digit in { (74)188 x 72 }
= Unique digit in ( 1 x 49 ) = 9
First 15 multiple of 8 are 8, 16, 24, ......, 120
Sum = 8 (1 + 2 + 3 + 4 ......+ 15)
= 8 [ n(n + 1) / 2]
= 8 x 15 x 8
960
Sum of first n odd number = n2
Given, n = 37
? Required sum = 372
= 37 x 37
= 1369
Sum of first n even numbers = n( n +1 )
Given n = 84
? Required sum = 84 ( 84 + 1 )
= 84 x 85
= 7140
Sum of cubes of first n natural numbers = [ n(n+1) ]2
Given n = 15
? Required sum = [ ( 15 x 16 ) / 2 ] 2
= (15 x 8 )2
= 1202
= 14400
Let the number be N
According to question
N = 56k + 29
Then,
N = ( 8 x 7k ) + ( 8 x 3 ) + 5
Therefore if N will be divided by 8 the required remainder will = 5
Let the given number be N
Therefore N = 357k + 39
Then,
357 k + 39 = ( 17 x 21k ) + ( 17 x 2 ) + 5
? Required remainder = 5
Let the number be N.
Therefore N = 5k + 3
On squaring both sides, we get
N2 = ( 5k + 3)2
= 5( 5k2 + 6k +1 ) + 4
? On dividing x2 by 5, the remainder is 4
Let the divisor be x and quotient be y.
Then, the number = xy + 24
Twice the number = 2xy + 48
Now 2xy is completely divisible by x.
On dividing 48 by x remainder is x
? x = 48 - 11
= 37
We know that, a number is divisible by 11 when the sum of the difference between the sum of its digit at even places and sum of its digit at odd places is either 0 or the difference is divisible by 11.
So number is 58129745812974
Sum of digit at odd places = 4 + 9 + 1 + 5 + 7 + 2 + 8 = 36
Sum of digit at even places = 7 + 2 + 8 + 4 + 9 + 1 + 5 = 36
So, required difference = 36 - 36 = 0
? number is divisible by 11.
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