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  • Question
  • Subtraction of 1001011002 from 11101010102 is


  • Options
  • A. 10010111102
  • B. 01101000012
  • C. 11110000012
  • D. 11110111112
  • E. None of the above

  • Correct Answer
  • 10010111102 


  • Digital Computer Electronics problems


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    • 1. Which of the following logic expression is wrong?

    • Options
    • A. 1 + 0=1
    • B. 1 + 1=0
    • C. 1+0+1 = 1
    • D. 1 + 1 + 1 = 1
    • E. None of the above
    • Discuss
    • 2. A microcomputer is a computer that uses a _____ for its CPU.

    • Options
    • A. chips
    • B. registers
    • C. microprocessor
    • D. vacuum tube
    • E. None of the above
    • Discuss
    • 3. A NOR gate recognizes only the input word whose bits are _____

    • Options
    • A. 0's and 1's
    • B. 1's
    • C. 0's
    • D. 0's or 1's
    • E. None of the above
    • Discuss
    • 4. Which of the following boolean algebra statements represent commutative law

    • Options
    • A. (A+B)+CA+(B+C)
    • B. A.(B+C)(A.B)+(A.C)
    • C. A+BB+A
    • D. A+AA
    • E. None of the above
    • Discuss
    • 5. How many bytes are there in 1011 1001 0110 1110 numbers?

    • Options
    • A. 1
    • B. 2
    • C. 4
    • D. 8
    • E. None of the above
    • Discuss
    • 6. Parallel adders are

    • Options
    • A. combinational logic circuits
    • B. sequential logic circuits
    • C. both of the above
    • D. All of the above
    • E. None of the above
    • Discuss
    • 7. Consider as RS flip-flops with both inputs set to 0. If a momentary '1' is applied at the input S, then the output

    • Options
    • A. Q will flip from 0 to 1
    • B. Q will flip from 0 to 1 and then back to 0
    • C. Q will flip from 0 to 1
    • D. Q will flip from 0 to 1 and then back to 0
    • E. None of the above
    • Discuss
    • 8. The 2's compliment of binary number 0.01011 is:

    • Options
    • A. 1.10101
    • B. 0.10101
    • C. 1.10100
    • D. 0.10100
    • E. None of the above
    • Discuss
    • 9. Conversion of hexadecimal number 93FA16 to it's binary number equivalent is

    • Options
    • A. 10010011111110102
    • B. 100100111111101112
    • C. 1100111111100112
    • D. 1111100001112
    • E. None of the above
    • Discuss
    • 10. Conversion of an octal number 1348 to a binary number is

    • Options
    • A. 0010110112
    • B. 0011011002
    • C. 0010111002
    • D. 1100112
    • E. None of the above
    • Discuss


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