Discussion
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- Question
Conversion of an octal number 1368 to hexadecimal number is
Options- A. 7E16
- B. 5E16
- C. 5A16
- D. 5D16
- E. None of the above
- Correct Answer
- 5E16
- 1. The m-bit parallel adder consists of:
Options- A. (m+1) full adders
- B. m/2 full adders
- C. m-1 full adders
- D. m full adders
- E. None of the above Discuss
- 2. The maximum count which a 6-bit binary word can represent is
Options- A. 36
- B. 64
- C. 63
- D. 65
- E. None of the above Discuss
- 3. Addition of 11012 and 10102 is
Options- A. 101012
- B. 110002
- C. 110112
- D. 101112
- E. None of the above Discuss
- 4. Computer ICs work reliably because they are based on _____ design.
Options- A. Top-bottom
- B. System
- C. Two-stage
- D. Two-states
- E. None of the above Discuss
- 5. Resistor Ratio design is used in linear ICs because
Options- A. Ratios increase input resistance
- B. Ratios increase amplifier gain
- C. Precise resistor values are not possible with IC processes
- D. All of the above
- E. None of the above Discuss
- 6. What is the 1's complement of 0000 1111 0010 1101 number?
Options- A. 1111 0000 0010 1101
- B. 1111 0000 1101 0010
- C. 1111 1100 1010 1100
- D. 1001 0010 1010 1100
- E. None of the above Discuss
- 7. In which of the following adder circuits, the carry look ripple delay is eliminated?
Options- A. Half adder
- B. Full adder
- C. Parallel adder
- D. Carry-look-ahead adder
- E. None of the above Discuss
- 8. Conversion of an octal number 74328 to a binary number is
Options- A. 11110001101112
- B. 1111000110102
- C. 1100110101112
- D. 1111111110002
- E. None of the above Discuss
- 9. A NAND gate is equivalent to an AND gate followed by an inverter. All inputs must be _____ to get a low output
Options- A. low
- B. high
- C. some low and some high
- D. 0's
- E. None of the above Discuss
- 10. An OR gate has 6 inputs. How many input words are in its truth table?
Options- A. 64
- B. 32
- C. 16
- D. 128
- E. None of the above Discuss
Digital Computer Electronics problems
Search Results
Correct Answer: m full adders
Correct Answer: 63
Correct Answer: 101112
Correct Answer: Two-states
Correct Answer: Precise resistor values are not possible with IC processes
Correct Answer: 1111 0000 1101 0010
Correct Answer: Carry-look-ahead adder
Correct Answer: 1111000110102
Correct Answer: high
Correct Answer: 64
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