Wave guides are pressurised above normal atmospheric pressure for increasing the

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Question
Wave guides are pressurised above normal atmospheric pressure for
Options
A. increasing the power handling capacity
B. improving conductivity of walls
C. preventing higher modes from propagation
D. varying the wave impedance

Correct Answer

increasing the power handling capacity

Microwave Communication problems

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1. In a rectangular waveguide there is one half wave variation of electric field across the narrow dimension and two half wave variations of electric field across wider dimension. The dominant mode is
Options
A. TM₁₂
B. TE₁₃
C. TE₂₁
D. TM₂₅

2. When a wave reaches an open circuit
Options
A. the voltage at termination is doubled the incident voltage
B. the current at termination is doubled the incident voltage
C. the voltage at termination is zero
D. both V and I at termination are doubled the incident voltage and current

3. Assertion (A): In circular waveguide the attenuation of TE₀₁ mode decreases as the operating frequency increases.
Reason (R): The wall currents in a circular waveguide in TE_Q1 mode are completely circumferential.
Options
A. Both A and R are correct and R is correct explanation of A
B. Both A and R are correct but R is not correct explanation of A
C. A is correct but R is wrong
D. A is wrong but R is correct

4. In TE and TM modes of rectangular waveguides having propagation in z direction
Options
A. E_z and H_z are both zero
B. In TE mode E_z is zero and in TM mode H_z is zero
C. In TE mode H_z is zero and in TM mode E_z is zero
D. In both TE and TM modes both E_z and H_z are non-zero

5. Assertion (A): Two equal and opposite travelling waves result in a standing wave.
Reason (R): The ratio of maximum to minimum value of a standing wave is called SWR.
Options
A. Both A and R are correct and R is correct explanation of A
B. Both A and R are correct but R is not correct explanation of A
C. A is correct but R is wrong
D. A is wrong but R is correct

6. Assertion (A): In a power divider S_H = 0, S₂₁ = 0.707 = S₃,
Reason (R): In a power divider the input port (i.e., port 1) is matched and incident power is equally divided in output ports 2 and 3
Options
A. Both A and R are correct and R is correct explanation of A
B. Both A and R are correct but R is not correct explanation of A
C. A is correct but R is wrong
D. A is wrong but R is correct

7. The p mode of operation of magnetron signifies that
Options
A. the phase difference between adjacent anode poles is p radians
B. the phase difference between adjacent anode poles is a multiple of p radians
C. the total phase shift around the periphery is p radians
D. none of the above

10. Which of the following are true for magic tee in the given figure select the answer as per given codes
1. S₁₃ = S₂₃
2. S₁₄ = S₂₄
3. S₁₂ = 0
4. S₃₄ = 0
Options
A. 1, 2 and 3
B. 1, 2 and 4
C. 2, 3 and 4
D. 1, 3 and 4

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