Discussion
Home ‣ Electronics and Communication Engineering ‣ Microwave Communication Comments
- Question
In the given figure the reflected current wave after first reflection is
Options- A. 0.18 A
- B. -0.18 A
- C. 0.3 A
- D. -0.3 A
- Correct Answer
- -0.18 A
Explanation
Microwave Communication problems
Search Results
- 1. Which device has internal positive feedback?
Options- A. Two cavity klystron amplifier
- B. Multi-cavity klystron amplifier
- C. Reflex klystron amplifier
- D. All of the above Discuss
Correct Answer: Reflex klystron amplifier
Explanation:
A Klystron is a vacuum tube used for generation/amplification of microwaves.An electron beam is produced by oxide coated indirectly heated cathode and is focussed and accelerated by focussing electrode.
This beam is transmitted through a glass tube. The input cavity where the beam enters the glass tube is called buncher.
As electrons move ahead they see an accelerating field for half cycle and retarding field for the other half cycle.
Therefore, some electrons are accelerated and some are retarded. This process is called velocity modulation.
The velocity modulation causes bunching of electrons. This bunching effect converts velocity modulation into density modulation of beam.
The input is fed at buncher cavity and output is taken at catcher cavity.
In a two cavity klystron only buncher and catcher cavity are used. In multi cavity klystron one or more intermediate cavities are also used.
The features of a multicavity klystron are :
1. Frequency range - 0.25 GHz to 100 GHz
2. Power output - 10 kW to several hundred kW
3. Power gain - 60 dB (nominal value)
4. Efficiency - about 40%.
A multicavity klystron is used in UHF TV transmitters, Radar transmitter and satellite communication.
- 2. In the given figure the E and H lines in a coaxial cable
Options- A. The radial lines are E lines and circular lines are H lines
- B. Radial lines are H lines and circular lines are E lines
- C. The directions of E and H lines are wrong
- D. Radial lines may be E and H lines depending an direction of current Discuss
Correct Answer: The radial lines are E lines and circular lines are H lines
Explanation:
H lines are concentric circles around conductor and E lines are radial.- 3. In a multicavity klystron amplifier the signal to be amplified develops an ac voltage of signal frequency across the gap in buncher cavity
Options- A. True
- B. False Discuss
Correct Answer: True
Explanation:
A Klystron is a vacuum tube used for generation/amplification of microwaves.An electron beam is produced by oxide coated indirectly heated cathode and is focussed and accelerated by focussing electrode.
This beam is transmitted through a glass tube. The input cavity where the beam enters the glass tube is called buncher.
As electrons move ahead they see an accelerating field for half cycle and retarding field for the other half cycle.
Therefore, some electrons are accelerated and some are retarded. This process is called velocity modulation.
The velocity modulation causes bunching of electrons. This bunching effect converts velocity modulation into density modulation of beam.
The input is fed at buncher cavity and output is taken at catcher cavity.
In a two cavity klystron only buncher and catcher cavity are used. In multi cavity klystron one or more intermediate cavities are also used.
The features of a multicavity klystron are :
1. Frequency range - 0.25 GHz to 100 GHz
2. Power output - 10 kW to several hundred kW
3. Power gain - 60 dB (nominal value)
4. Efficiency - about 40%.
A multicavity klystron is used in UHF TV transmitters, Radar transmitter and satellite communication.
- 4. The number of TV channels which can be accommodated in a spectrum of 300 MHz is about
Options- A. 5
- B. 10
- C. 50
- D. 200 Discuss
Correct Answer: 50
Explanation:
A TV channel has a bandwidth about 5 MHz. Hence 300 MHz spectrum can accommodate about 50 channels.- 5. Which mode has the lowest cut off frequency in circular wave guides?
Options- A. TE01
- B. TE11
- C. TE20
- D. TE21 Discuss
Correct Answer: TE11
Explanation:
Some applications require dual polarization capability. Circular waveguide has this capability.These analysis uses cylindrical coordinates.
In circular waveguide TE11 mode has the lowest cut off frequency and is the dominant mode.
If D is diameter of waveguide
?c = 1.706 D for TE11 mode
?c = 1.029 D for TE21 mode
?c = 0.82 D for TE01 mode
?c = 1.306 D for TM01 mode.
- 6. Assertion (A): The velocity of electromagnetic waves on overhead lines and coaxial cables is the same.
Reason (R): Free space has an intrinsic impedance of 377 ohms.
Options- A. Both A and R are correct and R is correct explanation of A
- B. Both A and R are correct but R is not correct explanation of A
- C. A is correct but R is wrong
- D. A is wrong but R is correct Discuss
Correct Answer: A is wrong but R is correct
Explanation:
Velocity of em waves on caoxial cables is less than that on overhead lines.- 7. Assertion (A): Impedance matching can be done by using stubs.
Reason (R): A double stub is used for impedance matching when frequency of signal varies.
Options- A. Both A and R are correct and R is correct explanation of A
- B. Both A and R are correct but R is not correct explanation of A
- C. A is correct but R is wrong
- D. A is wrong but R is correct Discuss
Correct Answer: Both A and R are correct and R is correct explanation of A
Explanation:
Hollow metallic enclosures exhibit resonance behaviour when excited by electromagnetic field.These enclosures are called cavity resonators.
- 8. Atomic and molecular resonance is observed in many substances
Options- A. at microwave frequencies
- B. at low frequencies
- C. at frequencies used in AM broadcast
- D. at both (b) and (c) Discuss
Correct Answer: at microwave frequencies
Explanation:
Atomic and molecular distances are very small. Therefore resonance can occur only at microwave frequencies.- 9. The expression HZ = C cos(Bx) cos(Ay)yz is for
Options- A. TE wave
- B. TM waves
- C. both TE and TM waves
- D. some TE and some TM waves Discuss
Correct Answer: TE wave
Explanation:
In TM mode Hz = 0.- 10. If the minimum range of a radar is to be doubled, the peak power has to be increased by a factor of
Options- A. 2
- B. 4
- C. 8
- D. 16 Discuss
Correct Answer: 16
Explanation:
Range = (power)025.
Comments
There are no comments.
More in Electronics and Communication Engineering:
Programming
Copyright ©CuriousTab. All rights reserved.