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Advanced Surveying
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Question
The latitude of a place was obtained by subtracting the declination of a star from its zenith distance, the observed star was between
Options
A. horizon and equator
B. zenith and pole
C. equator and zenith
D. pole and horizon.
Correct Answer
horizon and equator
Advanced Surveying problems
Search Results
1. Triangulation surveys are carried out for providing
Options
A. planimetric control
B. height control
C. both planimetric and height control
D. none of these.
Show Answer
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Discuss
Correct Answer: both planimetric and height control
2. The angular distance of a heavenly body from the equator, measured along its meridian, is called
Options
A. declination
B. altitude
C. zenith distance
D. co-latitude.
Show Answer
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Discuss
Correct Answer: declination
3. The method of surveying by triangula-tion was first introduced by the Dutchman Snell in
Options
A. 1600
B. 1615
C. 1630
D. 1650
E. 1680.
Show Answer
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Correct Answer: 1615
4. The negative sign is assigned to
Options
A. reduction to mean sea level
B. correction for horizontal alignment
C. correction for slope
D. correction for slope
E. all the above.
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Correct Answer: all the above.
5. The point on the photograph where bisector between the vertical line through optical centre of the camera lens and the plate perpendicular meets, is known as
Options
A. principal point
B. isocentre
C. plumb point
D. perspective centre.
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Correct Answer: isocentre
6. When a star is between the pole and the horizon, the relationship between latitude (?), zenith distance (
z
) and declination ?, is
Options
A. ? =
z
+ ?
B. ? = ? -
z
C. ? = 180° - (
z
+ ?)
D. ? = (
z
+ ?) - 180°.
Show Answer
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Correct Answer: ? = 180° - (
z
+ ?)
7. The station pointer is generally used in
Options
A. Triangulation surveying
B. Astronomical surveying
C. Hydrographical surveying
D. Photogrammetric surveying.
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Correct Answer: Hydrographical surveying
8. For a spherical triangle
ABC
, pick up incorrect statement
Options
A.
B.
C.
D.
E. none of these.
Show Answer
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Correct Answer:
9. If
S
is the sum of three angles of a spherical triangle, the spherical excess equals
Options
A.
S
- 90°
B.
S
- 180°
C.
S
- 270°
D.
S
- 360°.
Show Answer
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Correct Answer:
S
- 180°
10. The true and mean suns occupy the same meridian at the same time on
Options
A. April 15
B. June 14
C. September 1
D. December 25
E. all the above.
Show Answer
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Discuss
Correct Answer: all the above.
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