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- Question
The method of surveying by triangula-tion was first introduced by the Dutchman Snell in
Options- A. 1600
- B. 1615
- C. 1630
- D. 1650
- E. 1680.
- Correct Answer
- 1615
- 1. The negative sign is assigned to
Options- A. reduction to mean sea level
- B. correction for horizontal alignment
- C. correction for slope
- D. correction for slope
- E. all the above. Discuss
- 2. The point on the photograph where bisector between the vertical line through optical centre of the camera lens and the plate perpendicular meets, is known as
Options- A. principal point
- B. isocentre
- C. plumb point
- D. perspective centre. Discuss
- 3. The difference of parallax for a given difference in elevation is independent of
Options- A. focal length of the camera
- B. overall size of the photo graphs
- C. percentage of overlap
- D. all the above. Discuss
- 4. The prime vertical passes through
Options- A. the east point of the horizon
- B. the west point of the horizon
- C. the zenith point of the observer
- D. the nadir point of horizon
- E. all the above. Discuss
- 5. Pick up the in-correct statement from the folowing :
Options- A. Correction for refraction is always negative
- B. Correction for parallax is always positive
- C. Correction for semi-diameter is always negative
- D. Correction for dip is always negative
- E. None of these. Discuss
- 6. The angular distance of a heavenly body from the equator, measured along its meridian, is called
Options- A. declination
- B. altitude
- C. zenith distance
- D. co-latitude. Discuss
- 7. Triangulation surveys are carried out for providing
Options- A. planimetric control
- B. height control
- C. both planimetric and height control
- D. none of these. Discuss
- 8. The latitude of a place was obtained by subtracting the declination of a star from its zenith distance, the observed star was between
Options- A. horizon and equator
- B. zenith and pole
- C. equator and zenith
- D. pole and horizon. Discuss
- 9. When a star is between the pole and the horizon, the relationship between latitude (?), zenith distance (z) and declination ?, is
Options- A. ? = z + ?
- B. ? = ? - z
- C. ? = 180° - (z + ?)
- D. ? = (z + ?) - 180°. Discuss
- 10. The station pointer is generally used in
Options- A. Triangulation surveying
- B. Astronomical surveying
- C. Hydrographical surveying
- D. Photogrammetric surveying. Discuss
Advanced Surveying problems
Search Results
Correct Answer: all the above.
Correct Answer: isocentre
Correct Answer: all the above.
Correct Answer: all the above.
Correct Answer: Correction for semi-diameter is always negative
Correct Answer: declination
Correct Answer: both planimetric and height control
Correct Answer: horizon and equator
Correct Answer: ? = 180° - (z + ?)
Correct Answer: Hydrographical surveying
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