Discussion
Home ‣ Civil Engineering ‣ Soil Mechanics and Foundation Engineering Comments
- Question
A pycnometer is used to determine
Options- A. voids ratio
- B. dry density
- C. water content
- D. density index.
- Correct Answer
- water content
- 1. Pick up the correct statement from the following:
Options- A. A maximum value of dry density is obtained at optimum water content
- B. At low value of water content most soils tend to be stiff.
- C. At high water content, the dry density decreases with an increase of water content.
- D. An airless soil will have maximum possible value of dry density for the given water content
- E. All the above. Discuss
- 2. The reduction in volume of soil due to squeezing out of water from the voids, is termed
Options- A. primary consolidation
- B. primary compression
- C. primary time effect
- D. all the above. Discuss
- 3. The angle of internal friction, is least for
Options- A. angular-grained loose sand
- B. angular -grained dense sand
- C. round-grained loose sand
- D. round-grained loose sand
- E. clays. Discuss
- 4. The ratio of the volume of water present in a given soil mass to the total volume of its voids, is known
Options- A. porosity
- B. void ratio
- C. percentage voids
- D. degree of saturation. Discuss
- 5. In a purely cohesive soil, the critical centre lies at the intersection of
Options- A. perpendicular bisector of slope and the locus of the centre
- B. perpendicular drawn at l/3rd slope from toe and the locus of the centre
- C. perpendicular drawn at 2/3rd slope from toe and the locus of the centre
- D. directional angles
- E. none of these. Discuss
- 6. Stoke's law does not hold good if the size of particle is smaller than
Options- A. 0.0002 mm
- B. 0.002 mm
- C. 0.02 mm
- D. 0.2 mm Discuss
- 7. Plasticity index is defined as the range of water content between
Options- A. liquid and plastic limit
- B. plastic limit and semi solid limit
- C. semi-solid limit and liquid limit
- D. liquid limit and solid limit. Discuss
- 8. The shear strength in plastic undrained clay, is due to
Options- A. inter-granular friction
- B. internal friction
- C. cohesion
- D. none of these. Discuss
- 9. In non-cohesive soil in passive state of plastic equilibrium
Options- A. major principal stress is horizontal
- B. minor principal stress is vertical
- C. major principal stress is vertical
- D. minor and major principal stresses are equally inclined to the horizontal. Discuss
- 10. According to IS : 2720 - 1965, the composition of a dispersing solution used in pipette analysis for determining the size of particles, is
Options- A. sodium-hexametaphosphate 33 g, sodium carbonate 7 g and distilled water one litre
- B. sodium-hexametaphosphate 7 g, sodium carbonate 33 g and distilled water one litre
- C. sodium-hexametaphosphate 23 g, sodium carbonate 17 g and distilled water one litre
- D. none of these. Discuss
Soil Mechanics and Foundation Engineering problems
Search Results
Correct Answer: All the above.
Correct Answer: all the above.
Correct Answer: clays.
Correct Answer: degree of saturation.
Correct Answer: directional angles
Correct Answer: 0.0002 mm
Correct Answer: liquid and plastic limit
Correct Answer: cohesion
Correct Answer: minor principal stress is vertical
Correct Answer: sodium-hexametaphosphate 33 g, sodium carbonate 7 g and distilled water one litre
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