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  • Question
  • The weight of the LSB as a binary number is:


  • Options
  • A. 1
  • B. 2
  • C. 3
  • D. 4

  • Correct Answer



  • Number Systems and Codes problems


    Search Results


    • 1. Convert the binary number 1001.0010 to decimal.

    • Options
    • A. 125
    • B. 12.5
    • C. 90.125
    • D. 9.125
    • Discuss
    • 2. What is the decimal value of the hexadecimal number 777?

    • Options
    • A. 191
    • B. 1911
    • C. 19
    • D. 19111
    • Discuss
    • 3. 3428 is the decimal value for which of the following binary coded decimal (BCD) groupings?

    • Options
    • A. 11010001001000
    • B. 11010000101000
    • C. 011010010000010
    • D. 110100001101010
    • Discuss
    • 4. Which is the TRIAC?

    • Options
    • A.
    • B.
    • C.
    • D.
    • Discuss
    • 5. What type of application would use an injection laser diode?

    • Options
    • A. a 10BASE-T Ethernet
    • B. a liquid crystal display
    • C. a fiber optic transmission line
    • D. a good flashlight
    • Discuss
    • 6. What is the result when a decimal 5238 is converted to base 16?

    • Options
    • A. 327.375
    • B. 12166
    • C. 1388
    • D. 1476
    • Discuss
    • 7. Convert the decimal number 151.75 to binary.

    • Options
    • A. 10000111.11
    • B. 11010011.01
    • C. 00111100.00
    • D. 10010111.11
    • Discuss
    • 8. The number of bits used to store a BCD digit is:

    • Options
    • A. 8
    • B. 4
    • C. 1
    • D. 2
    • Discuss
    • 9. Base 10 refers to which number system?

    • Options
    • A. binary coded decimal
    • B. decimal
    • C. octal
    • D. hexadecimal
    • Discuss
    • 10. Sample-and-hold circuits in ADCs are designed to:

    • Options
    • A. sample and hold the output of the binary counter during the conversion process
    • B. stabilize the ADCs threshold voltage during the conversion process
    • C. stabilize the input analog signal during the conversion process
    • D. sample and hold the ADC staircase waveform during the conversion process
    • Discuss


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