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- Question
Using the following illustration, what would be the IP address of E0 if you were using the eighth subnet? The network ID is 192.168.10.0/28 and you need to use the last available IP address in the range. The zero subnet should not be considered valid for this question.
Options- A. 192.168.10.142
- B. 192.168.10.66
- C. 192.168.100.254
- D. 192.168.10.143
- E. 192.168.10.126
- Correct Answer
- 192.168.10.142
ExplanationA /28 is a 255.255.255.240 mask. Let's count to the ninth subnet (we need to find the broadcast address of the eighth subnet, so we need to count to the ninth subnet). Starting at 16 (remember, the question stated that we will not use subnet zero, so we start at 16, not 0), 16, 32, 48, 64, 80, 96, 112, 128, 144. The eighth subnet is 128 and the next subnet is 144, so our broadcast address of the 128 subnet is 143. This makes the host range 129-142. 142 is the last valid host. - 1. Which two statements describe the IP address 10.16.3.65/23?
- The subnet address is 10.16.3.0 255.255.254.0.
- The lowest host address in the subnet is 10.16.2.1 255.255.254.0.
- The last valid host address in the subnet is 10.16.2.254 255.255.254.0.
- The broadcast address of the subnet is 10.16.3.255 255.255.254.0.
Options- A. 1 and 3
- B. 2 and 4
- C. 1, 2 and 4
- D. 2, 3 and 4 Discuss
- 2. Which of the following types of connections can use full duplex?
- Hub to hub
- Switch to switch
- Host to host
- Switch to hub
- Switch to host
Options- A. 1, 2 and 4
- B. 3 and 4
- C. 3 and 5
- D. 2, 3 and 5 Discuss
- 3. Acknowledgments, sequencing, and flow control are characteristics of which OSI layer?
Options- A. Layer 2
- B. Layer 3
- C. Layer 4
- D. Layer 7 Discuss
- 4. What type of RJ45 UTP cable is used between switches?
Options- A. Straight-through
- B. Crossover cable
- C. Crossover with a CSU/DSU
- D. Crossover with a router in between the two switches Discuss
- 5. What are the decimal and hexadecimal equivalents for the binary number 10110111?
Options- A. 69/0x2102
- B. 183/B7
- C. 173/A6
- D. 83/0xC5 Discuss
- 6. The network address of 172.16.0.0/19 provides how many subnets and hosts?
Options- A. 7 subnets, 30 hosts each
- B. 8 subnets, 8,190 hosts each
- C. 8 subnets, 2,046 hosts each
- D. 7 subnets, 2,046 hosts each Discuss
- 7. Your router has the following IP address on Ethernet0: 172.16.2.1/23. Which of the following can be valid host IDs on the LAN interface attached to the router?
- 172.16.1.100
- 172.16.1.198
- 172.16.2.255
- 172.16.3.0
Options- A. 1 only
- B. 2 and 3 only
- C. 3 and 4 only
- D. None of the above Discuss
- 8. You have an interface on a router with the IP address of 192.168.192.10/29. Including the router interface, how many hosts can have IP addresses on the LAN attached to the router interface?
Options- A. 6
- B. 8
- C. 30
- D. 32 Discuss
- 9. To test the IP stack on your local host, which IP address would you ping?
Options- A. 127.0.0.0
- B. 1.0.0.127
- C. 127.0.0.1
- D. 127.0.0.255 Discuss
- 10. What is the subnetwork address for a host with the IP address 200.10.5.68/28?
Options- A. 200.10.5.56
- B. 200.10.5.32
- C. 200.10.5.64
- D. 200.10.5.0 Discuss
Subnetting problems
Search Results
Correct Answer: 2 and 4
Explanation:
The mask 255.255.254.0 (/23) used with a Class A address means that there are 15 subnet bits and 9 host bits. The block size in the third octet is 2 (256 - 254). So this makes the subnets in the interesting octet 0, 2, 4, 6, etc., all the way to 254. The host 10.16.3.65 is in the 2.0 subnet. The next subnet is 4.0, so the broadcast address for the 2.0 subnet is 3.255. The valid host addresses are 2.1 through 3.254.
Correct Answer: 2, 3 and 5
Explanation:
Hubs cannot run full-duplex Ethernet. Full duplex must be used on a point-to-point connection between two devices capable of running full duplex. Switches and hosts can run full duplex between each other, but a hub can never run full duplex.
Correct Answer: Layer 4
Explanation:
A reliable Transport layer connection uses acknowledgments to make sure all data is transmitted and received reliably. A reliable connection is defined by a virtual circuit that uses acknowledgments, sequencing, and flow control, which are characteristics of the Transport layer (layer 4).
Correct Answer: Crossover cable
Explanation:
To connect two switches together, you would use a RJ45 UTP crossover cable.
Correct Answer: 183/B7
Explanation:
You must be able to take a binary number and convert it into both decimal and hexadecimal. To convert to decimal, just add up the 1s using their values. The values that are turned on with the binary number of
10110111 are
128 + 32 + 16 + 4 + 2 + 1 = 183. To get the hexadecimal equivalent, you need to break the eight binary digits into nibbles (4 bits),
1011 and
0111. By add- ing up these values, you get
11 and
7. In hexadecimal,
11 is
B, so the answer is
0xB7.
Correct Answer: 8 subnets, 8,190 hosts each
Explanation:
A CIDR address of /19 is 255.255.224.0. This is a Class B address, so that is only 3 subnet bits, but it provides 13 host bits, or 8 subnets, each with 8,190 hosts.
Correct Answer: 3 and 4 only
Explanation:
The router's IP address on the E0 interface is 172.16.2.1/23, which is 255.255.254.0. This makes the third octet a block size of 2. The router's interface is in the 2.0 subnet, and the broadcast address is 3.255 because the next subnet is 4.0. The valid host range is 2.1 through 3.254. The router is using the first valid host address in the range.
Correct Answer: 6
Explanation:
A /29 (255.255.255.248), regardless of the class of address, has only 3 host bits. Six hosts is the maximum number of hosts on this LAN, including the router interface.
Correct Answer: 127.0.0.1
Explanation:
To test the local stack on your host, ping the loopback interface of 127.0.0.1.
Correct Answer: 200.10.5.64
Explanation:
This is a pretty simple question. A /28 is 255.255.255.240, which means that our block size is 16 in the fourth octet. 0, 16, 32, 48, 64, 80, etc. The host is in the 64 subnet.
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