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- Question
Which two statements describe the IP address 10.16.3.65/23?
- The subnet address is 10.16.3.0 255.255.254.0.
- The lowest host address in the subnet is 10.16.2.1 255.255.254.0.
- The last valid host address in the subnet is 10.16.2.254 255.255.254.0.
- The broadcast address of the subnet is 10.16.3.255 255.255.254.0.
Options- A. 1 and 3
- B. 2 and 4
- C. 1, 2 and 4
- D. 2, 3 and 4
- Correct Answer
- 2 and 4
ExplanationThe mask 255.255.254.0 (/23) used with a Class A address means that there are 15 subnet bits and 9 host bits. The block size in the third octet is 2 (256 - 254). So this makes the subnets in the interesting octet 0, 2, 4, 6, etc., all the way to 254. The host 10.16.3.65 is in the 2.0 subnet. The next subnet is 4.0, so the broadcast address for the 2.0 subnet is 3.255. The valid host addresses are 2.1 through 3.254. - 1. What command will permit SMTP mail to only host 1.1.1.1?
Options- A. access-list 10 permit smtp host 1.1.1.1
- B. access-list 110 permit ip smtp host 1.1.1.1
- C. access-list 10 permit tcp any host 1.1.1.1 eq smtp
- D. access-list 110 permit tcp any host 1.1.1.1 eq smtp Discuss
- 2. The Corporate router receives an IP packet with a source IP address of 192.168.214.20 and a destination address of 192.168.22.3. Looking at the output from the Corporate router, what will the router do with this packet?
Corp#sh ip route [output cut] R 192.168.215.0 [120/2] via 192.168.20.2, 00:00:23, Serial0/0 R 192.168.115.0 [120/1] via 192.168.20.2, 00:00:23, Serial0/0 R 192.168.30.0 [120/1] via 192.168.20.2, 00:00:23, Serial0/0 C 192.168.20.0 is directly connected, Serial0/0 C 192.168.214.0 is directly connected, FastEthernet0/0
Options- A. The packet will be discarded.
- B. The packet will be routed out the S0/0 interface.
- C. The router will broadcast looking for the destination.
- D. The packet will be routed out the Fa0/0 interface. Discuss
- 3. Which statement(s) about IPv4 and IPv6 addresses are true?
- An IPv6 address is 32 bits long, represented in hexidecimal.
- An IPv6 address is 128 bits long, represented in decimal.
- An IPv4 address is 32 bits long, represented in decimal.
- An IPv6 address is 128 bits long, represented in hexidecimal.
Options- A. 1 and 3 only
- B. 2 only
- C. 3 and 4
- D. 2 and 4 Discuss
- 4. When a new trunk link is configured on an IOS-based switch, which VLANs are allowed over the link?
Options- A. By default, all VLANs are allowed on the trunk.
- B. No VLAN's are allowed, you must configure each VLAN by hand.
- C. Only configured VLAN's are allowed on the link.
- D. Only extended VLAN's are allowed by default. Discuss
- 5. In Cisco's Unified Wireless Solution, what is the split-MAC architecture?
Options- A. The split-MAC architecture uses MAC addresses to create a forward/filter table and break up collision domains.
- B. The split-MAC architecture allows the splitting of 802.11 protocol packets between the AP and the controller to allow processing by both devices.
- C. The split-MAC architecture uses MAC addresses on the wireless network and IP addresses on the wired network.
- D. The split-MAC architecture uses MAC addresses to create a forward/filter table and break up broadcast domains. Discuss
- 6. You are working on a router that has established privilege levels that restrict access to certain functions. You discover that you are not able to execute the command show running-configuration. How can you view and confirm the access lists that have been applied to the Ethernet 0 interface on your router?
Options- A. show access-lists
- B. show interface Ethernet 0
- C. show ip access-lists
- D. show ip interface Ethernet 0 Discuss
- 7. What information is displayed by the show hosts command?
- Temporary DNS entries
- The names of the routers created using the hostname command
- The IP addresses of workstations allowed to access the router
- Permanent name-to-address mappings created using the ip host command
- The length of time a host has been connected to the router via Telnet
Options- A. 1, 2 and 3
- B. 1 and 4
- C. 3, 4, and 5
- D. All of the above Discuss
- 8. You want to create a standard access list that denies the subnet of the following host: 172.16.144.17/21. Which of the following would you start your list with?
Options- A. access-list 10 deny 172.16.48.0 255.255.240.0
- B. access-list 10 deny 172.16.144.0 0.0.7.255
- C. access-list 10 deny 172.16.64.0 0.0.31.255
- D. access-list 10 deny 172.16.136.0 0.0.15.255 Discuss
- 9. Your company is running IGRP using an AS of 10. You want to configure EIGRP on the network but want to migrate slowly to EIGRP and don't want to configure redistribution. What command would allow you to migrate over time to EIGRP without configuring redistribution?
Options- A. router eigrp 11
- B. router eigrp 10
- C. router eigrp 10 redistribute igrp
- D. router igrp combine eigrp 10 Discuss
- 10. Which of the following commands sets a trunk port on a 2960 switch?
Options- A. trunk on
- B. trunk all
- C. switchport trunk on
- D. switchport mode trunk Discuss
More questions
Correct Answer: access-list 110 permit tcp any host 1.1.1.1 eq smtp
Explanation:
When trying to find the best answer to an access-list question, always check the access-list number and then the protocol. When filtering to an upper-layer protocol, you must use an extended list, numbers 100-199 and 2000-2699. Also, when you filter to an upper-layer protocol, you must use either
tcp or
udp in the protocol field. If it says
ip in the protocol field, you cannot filter to an upper-layer protocol. SMTP uses TCP.
Correct Answer: The packet will be discarded.
Explanation:
Since the routing table shows no route to the 192.168.22.0 network, the router will discard the packet and send an ICMP destination unreachable message out interface FastEthernet 0/0, which is the source LAN where the packet originated from.
Correct Answer: 3 and 4
Explanation:
IPv4 addresses are 32 bits long and are represented in decimal format. IPv6 addresses are 128 bits long and represented in hexadecimal format.
Correct Answer: By default, all VLANs are allowed on the trunk.
Explanation:
By default, all VLANs are allowed on the trunk link and you must remove by hand each VLAN that you don't want traversing the trunked link.
Correct Answer: The split-MAC architecture allows the splitting of 802.11 protocol packets between the AP and the controller to allow processing by both devices.
Explanation:
The split-MAC architecture allows the splitting of 802.11 protocol packets between the Cisco LWAPP-based AP, which handles real-time portions of the protocol, and the WLAN controller, which handles those items that are not time sensitive.
Correct Answer: show ip interface Ethernet 0
Explanation:
The only command that shows which access lists have been applied to an interface is
show ip interface Ethernet 0. The command
show access-lists displays all configured access lists, and
show ip access-lists displays all configured IP access lists, but neither command indicates whether the displayed access lists have been applied to an interface.
Correct Answer: 1 and 4
Explanation:
The
show hosts command provides information on temporary DNS entries and permanent name-to-address mappings created using the
ip host command.
Correct Answer: access-list 10 deny 172.16.144.0 0.0.7.255
Explanation:
First, you must know that a /21 is 255.255.248.0, which is a block size of 8 in the third octet. Counting by eight, this makes our subnet 144 in the third octet, and the wildcard for the third octet would be 7 since the wildcard is always one less than the block size.
Correct Answer: router eigrp 10
Explanation:
If you enable EIGRP on a router with the same autonomous system (AS) number, EIGRP will automatically redistribute IGRP into EIGRP. You will see the IGRP injected routes as external (EX) routes with an EIGRP AD of 170. This is a nice feature that lets you migrate slowly to EIGRP with no extra configuration.
Correct Answer: switchport mode trunk
Explanation:
To set a switch port to trunk mode, which allows all VLAN information to pass down the link, use the
switchport mode trunk command.
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