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- Question
A 140 Ω resistor is in parallel with an inductor having 60 Ω inductive reactance. Both components are across a 12 V ac source. The magnitude of the total impedance is
Options- A. 5.51 Ω
- B. 55.15 Ω
- C. 90 Ω
- D. 200 Ω
- Correct Answer
- 55.15 Ω
- 1. A phasor represents
Options- A. the magnitude and a quantity direction
- B. the width of a quantity
- C. the phase angle
- D. the magnitude of a quantity Discuss
- 2. The voltages in Problem 4 are measured at a certain frequency. To make the capacitor voltage greater than the resistor voltage, the frequency
Options- A. must be increased
- B. must be decreased
- C. is held constant
- D. has no effect Discuss
- 3. A parallel resonant band-pass filter consists of a 6.8 Ω resistor in series with a parallel network made up of an 8 µH coil and a 120 pF capacitor. The output is taken across the capacitor/coil. Assume RW = 0 Ω. What is the center frequency of the filter?
Options- A. 5.14 MHz
- B. 514 kHz
- C. 5.03 MHz
- D. 503 kHz Discuss
- 4. The currents into a junction flow along two paths. One current is 4 A and the other is 3 A. The total current out of the junction is
Options- A. 1 A
- B. 7 A
- C. unknown
- D. the larger of the two Discuss
- 5. Four equal-value resistors are connected in parallel. Ten volts are applied across the parallel circuit and 2 mA are measured from the source. The value of each resistor is
Options- A. 12.5 Ω
- B. 200 Ω
- C. 20 KΩ
- D. 50 Ω Discuss
- 6. Eight-tenths coulomb passes a point in 4 s. The current in amperes is
Options- A. 1.6 A
- B. 16 A
- C. 2 A
- D. 0.2 A Discuss
- 7. The output of a certain voltage divider is 12 V with no load. When a load is connected, the output voltage
Options- A. decreases
- B. increases
- C. remains the same
- D. becomes zero Discuss
- 8. The complex number 6 + j6 is equivalent to
Options- A. 6∠45°
- B. 36∠45°
- C. 8.48∠45°
- D. 8.48∠90° Discuss
- 9. Generally, the mesh current method results in fewer equations than the node voltage method.
Options- A. True
- B. False Discuss
- 10. If there are a total of 120 mA into a parallel circuit consisting of three branches, and two of the branch currents are 40 mA and 10 mA, the third branch current is
Options- A. 50 mA
- B. 70 mA
- C. 120 mA
- D. 40 mA Discuss
More questions
Correct Answer: the magnitude and a quantity direction
Correct Answer: must be decreased
Correct Answer: 5.14 MHz
Correct Answer: 7 A
Correct Answer: 20 KΩ
Explanation:
10/(R/4) = 2 mA
40/R = 2 mA
R = 40/2 mA
= 40/0.002 A
= 20000 kohm (20 kohm)
40/R = 2 mA
R = 40/2 mA
= 40/0.002 A
= 20000 kohm (20 kohm)
Correct Answer: 0.2 A
Correct Answer: decreases
Correct Answer: 8.48∠45°
Correct Answer: False
Correct Answer: 70 mA
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