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- Question
Two series capacitors (one 2 µF, the other of unknown value) are charged from a 24 V source. The 2 µF capacitor is charged to 16 V and the other to 8 V. The value of the unknown capacitor is
Options- A. 1 µF
- B. 2 µF
- C. 4 µF
- D. 8 µF
- Correct Answer
- 4 µF
- 1. When converting 7,000 nA to microamperes, the result is
Options- A. 0.007 µA
- B. 0.7 µA
- C. 700 µA
- D. 7 µA Discuss
- 2. A series circuit has a 24 V source and a total resistance of 120 Ω. The current through each resistor is
Options- A. 24 mA
- B. 200 mA
- C. 120 mA
- D. 20 mA Discuss
- 3. In a parallel circuit, the branch with the lowest resistance has the most current.
Options- A. True
- B. False Discuss
- 4. How many degrees are there in Π/3 rad?
Options- A. 6°
- B. 60°
- C. 180°
- D. 27° Discuss
- 5. In an electric circuit, the reaction of a circuit to a given pulse input is known as the pulse response.
Options- A. True
- B. False Discuss
- 6. When an open circuit occurs in a parallel branch, the total resistance decreases.
Options- A. True
- B. False Discuss
- 7. The quantity 43 × 10-3 is the same as
Options- A. 0.043
- B. 0.430
- C. 430
- D. 43,000 Discuss
- 8. The resistor voltage is always out of phase with the current.
Options- A. True
- B. False Discuss
- 9. Transistors act basically as voltage sources.
Options- A. True
- B. False Discuss
- 10. At a certain frequency, the output voltage of a filter is 6 V and the input is 12 V. The voltage ratio in decibels is
Options- A. 6.02 dB
- B. ?6.02 dB
- C. 12.04 dB
- D. ?12.04 dB Discuss
More questions
Correct Answer: 7 µA
Correct Answer: 200 mA
Correct Answer: True
Correct Answer: 60°
Correct Answer: True
Correct Answer: False
Correct Answer: 0.043
Correct Answer: False
Correct Answer: False
Correct Answer: ?6.02 dB
Comments
Hello
Q=c'×v' =2×16 =32 ¶f Q=C2×v2 C2=32/8 C2=4 ¶f Therefore charge is unknown capacitor is 4 micro farad
Q=c'×v' =2×16 =32 ¶f Q=C2×v2 C2=32/8 C2=4 ¶f Therefore charge is unknown capacitor is 4 micro farad
?
Q=c'×v' =2×16 =32 ¶f Q=C2×v2 C2=32/8 C2=4 ¶f Therefore charge is unknown capacitor is 4 micro farad
Q=c'×v' =2×16 =32 ¶f Q=C2×v2 C2=32/8 C2=4 ¶f Therefore charge is unknown capacitor is 4 micro farad
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Q=c'×v' =2×16 =32 ¶f Q=C2×v2 C2=32/8 C2=4 ¶f Therefore charge is unknown capacitor is 4 micro farad