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- Question
A certain appliance uses 350 W. If it is allowed to run continuously for 24 days, how many kilowatt-hours of energy does it consume?
Options- A. 20.16 kWh
- B. 201.6 kWh
- C. 2.01 kWh
- D. 8.4 kWh
- Correct Answer
- 201.6 kWh
- 1. A 6 V battery is connected to a 300 Ω load. Under these conditions, it is rated at 40 Ah. How long can it supply current to the load?
Options- A. 1 h
- B. 200 h
- C. 2,000 h
- D. 10 h Discuss
- 2. A half-watt is equal to how many milliwatts?
Options- A. 5,000 mW
- B. 5 mW
- C. 500 mW
- D. 50 mW Discuss
- 3. In 40 kW, there are
Options- A. 0.4 mW
- B. 40,000 W
- C. 400 W
- D. 5,000 W Discuss
- 4. When the current through a 12 kΩ resistor is 8 mA, the power is
Options- A. 7.68 mW
- B. 768 mW
- C. 7.68 W
- D. 76.8 W Discuss
- 5. The power rating of a carbon-composition resistor that is to handle up to 1.2 W should be
Options- A. 2 W
- B. 1 W
- C. 5 W
- D. 0.5 W Discuss
- 6. How much continuous current can be drawn from a 60 Ah battery for 14 h?
Options- A. 42.8 A
- B. 428 A
- C. 4.28 A
- D. 4.2 A Discuss
- 7. A 470 Ω resistor, a 220 Ω resistor, and a 100 Ω resistor are all in parallel. The total resistance is approximately
Options- A. 790 Ω
- B. 470 Ω
- C. 60 Ω
- D. 30 Ω Discuss
- 8. Five 100 Ω resistors are connected in parallel. If one resistor is removed, the total resistance is
Options- A. 25 Ω
- B. 500 Ω
- C. 100 Ω
- D. 20 Ω Discuss
- 9. Three lights are connected in parallel across a 120 volt source. If one light burns out,
Options- A. the remaining two will glow dimmer
- B. the remaining two will glow brighter
- C. the remaining two will not light
- D. the remaining two will glow with the same brightness as before Discuss
- 10. In a five-branch parallel circuit, there are 12 mA of current in each branch. If one of the branches opens, the current in each of the other four branches is
Options- A. 48 mA
- B. 12 mA
- C. 0 A
- D. 3 mA Discuss
Energy and Power problems
Search Results
Correct Answer: 2,000 h
Correct Answer: 500 mW
Correct Answer: 40,000 W
Correct Answer: 768 mW
Correct Answer: 2 W
Correct Answer: 4.28 A
Correct Answer: 60 Ω
Explanation:
1/R = (1/470 + 1/220 + 1/100)
R = 59.98 ohm
R = 59.98 ohm
Correct Answer: 25 Ω
Explanation:
1/R = 1/R1 + 1/R2 + 1/R3 + 1/R4 1/R = 1/100 + 1/100 + 100 + 1/100 1/R = 4/100 1/R = 1/25 Therefore R = 25 ohm.
Correct Answer: the remaining two will glow with the same brightness as before
Correct Answer: 12 mA
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