A three-phase △-connected generator is driving a balanced load such that each phase current is 12 A in magnitude. When I ?a = 12 ∠30° A, what are the polar expressions for the other phase currents?
Options
A. I?b = 12 ∠150° A, I?c = 12∠?90° A
B. I?b = 12∠120° A, I?c = 12∠30° A
C. I?b = 12∠30° A, I?c = 12∠120° A
D. I?b = 12∠90° A, I?c = 12∠90° A
Correct Answer
I?b = 12 ∠150° A, I?c = 12∠?90° A
More questions
1. When the current through a 12 kΩ resistor is 8 mA, the power is
Because of 10% tolerance(last color silver), this resistance may vary 10% of 6800.
Minimum resistance value = 6800 - 680 = 6120
Maximum resistance value = 6800 + 680 = 7480
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