A 12 kΩ resistor is in series with a 0.02 µF capacitor across a 1.2 kHz ac source. If the current is expressed in polar form as I = 0.3∠0° mA, what is the source voltage expressed in polar form?
Options
A. 45.6 V
B. 411.3 V
C. 0.411 V
D. 4.11 V
Correct Answer
4.11 V
More questions
1. When the current through a 12 kΩ resistor is 8 mA, the power is
Because of 10% tolerance(last color silver), this resistance may vary 10% of 6800.
Minimum resistance value = 6800 - 680 = 6120
Maximum resistance value = 6800 + 680 = 7480
9. Four 8 Ω speakers are connected in parallel to the output of an audio amplifier. If the maximum voltage to the speakers is 12 V, the amplifier must be able to deliver to the speakers