Discussion
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- Question
An ohmmeter is connected across an inductor and the pointer indicates zero ohms. The inductor is
Options- A. good
- B. open
- C. shorted
- D. partly shorted
- Correct Answer
- shorted
- 1. An inductance of 0.08 µH is larger than
Options- A. 0.0000008 H
- B. 0.000000008 H
- C. 0.000008 H
- D. 0.00008 mH Discuss
- 2. The current through a 120 mH coil is changing at a rate of 150 mA/s. The voltage induced across the coil is
Options- A. 1.8 mV
- B. 18 mV
- C. 180 mV
- D. 1.25 mV Discuss
- 3. The voltage across a coil when di/dt = 20 mA/µs and L = 8 µH is
Options- A. 16 mV
- B. 160 mV
- C. 1.6 mV
- D. 2.5 mV Discuss
- 4. A 2 mH, a 3.3 mH, and a 0.2 mH inductor are connected in series. The total inductance is
Options- A. 55 mH
- B. less than 0.2 mH
- C. less than 5.5 mH
- D. 5.5 mH Discuss
- 5. An inductance of 0.43 mH is smaller than
Options- A. 43 µH
- B. 430 µH
- C. 0.05 H
- D. 0.00043 H Discuss
- 6. A 47 Ω resistor and a capacitor with 150 Ω of capacitive reactance are in series across an ac source. The impedance, expressed in rectangular form, is
Options- A. Z = 47 Ω + j150 Ω
- B. Z = 47 Ω ? j150 Ω
- C. Z = 197 Ω
- D. Z = 103 Ω Discuss
- 7. In the complex plane, the number 14 ? j5 is located in the
Options- A. first quadrant
- B. second quadrant
- C. third quadrant
- D. fourth quadrant Discuss
- 8. The complex number 40∠ 55° is equivalent to
Options- A. 55 + j55
- B. 40 + j40
- C. 45.88 + j65.52
- D. 22.94 + j32.76 Discuss
- 9. The complex number 6 + j6 is equivalent to
Options- A. 6∠45°
- B. 36∠45°
- C. 8.48∠45°
- D. 8.48∠90° Discuss
- 10. A 47 Ω resistor and a capacitor with a capacitive reactance of 120 Ω are in series across an ac source. What is the circuit impedance, Z?
Options- A. 129 Ω
- B. 12.9 Ω
- C. 167 Ω
- D. 73 Ω Discuss
Inductors problems
Search Results
Correct Answer: 0.000000008 H
Correct Answer: 18 mV
Correct Answer: 160 mV
Correct Answer: 5.5 mH
Correct Answer: 0.05 H
Correct Answer: Z = 47 Ω ? j150 Ω
Correct Answer: fourth quadrant
Correct Answer: 22.94 + j32.76
Correct Answer: 8.48∠45°
Correct Answer: 129 Ω
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