Discussion
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- Question
When these numbers are added, (87 × 105) + (2.5 × 106), the result is
Options- A. 1.12 × 104
- B. 11.2 × 105
- C. 112 × 105
- D. 1,120 × 106
- Correct Answer
- 112 × 105
- 1. The number of millivolts in 0.06 kilovolts is
Options- A. 600 V
- B. 6,000 mV
- C. 60,000 mV
- D. 600,000 mV Discuss
- 2. Seven thousand volts can be expressed as
Options- A. 7 kV
- B. 7 MV
- C. 7 mV
- D. either 7 kV or 7 mV Discuss
- 3. The quantity 3.3 × 103 is the same as
Options- A. 330
- B. 3,300
- C. 33,000
- D. 0.0033 Discuss
- 4. Eighteen thousand watts is the same as
Options- A. 18 mW
- B. 18 MW
- C. 18 kW
- D. 18 µW Discuss
- 5. The number 4.4 × 106 ohms expressed using a metric prefix is
Options- A. 4 k
- B. 4.4 k
- C. 4 M
- D. 4.4 M Discuss
- 6. When these numbers are multiplied, (6 × 103) (5 × 105), the result is
Options- A. 3 × 108
- B. 30 × 108
- C. 300 × 109
- D. 3,000 × 107 Discuss
- 7. The number 65,000 expressed in scientific notation as a number between 1 and 10 times a power of ten is
Options- A. 0.65 × 104
- B. 6.5 × 104
- C. 65 × 104
- D. 650 × 103 Discuss
- 8. What is the approximate resistance of a rheostat if the voltage source is 18 V and the current is 220 mA?
Options- A. 8.2 kΩ
- B. 820 Ω
- C. 8.2 Ω
- D. 82 Ω Discuss
- 9. When there is 12 mA of current through a 1.2 kΩ resistor, the voltage across the resistor is
Options- A. 14.4 V
- B. 1.4 V
- C. 100 V
- D. 10 V Discuss
- 10. A 120 V lamp-dimming circuit is controlled by a rheostat and protected from excessive current by a 3 A fuse. To what minimum resistance value can the rheostat be set without blowing the fuse? Assume a lamp resistance of 20 ohms.
Options- A. 40 Ω
- B. 4 Ω
- C. 2 Ω
- D. 20 Ω Discuss
Quantities and Units problems
Search Results
Correct Answer: 60,000 mV
Correct Answer: 7 kV
Correct Answer: 3,300
Correct Answer: 18 kW
Correct Answer: 4.4 M
Correct Answer: 30 × 108
Correct Answer: 6.5 × 104
Correct Answer: 82 Ω
Correct Answer: 14.4 V
Explanation:
V = IR (Ohms Law)
= 12 X 10-3 X 1.2 X 10 3
= 12 X 1.2
= 14.4 V
Correct Answer: 20 Ω
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