Z = R2 + XC2 = 50
V = 550 sin(20000 t - 45°)
V = 252 sin(20000 t - 45°)
= 2H log2 V bits/sec
V - discrete levels (Here Binary i.e. 2)
H - Bandwidth
? Maximum data rate = 2H log2 V
= 2(3 KHz) log2 2 = 2 x 3 x 103 x 1
= 6 x 103 = 6000 bps.
Reason (R): A GTO can be turned off by negative gate pulse.
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