Minimum number of 2-input NAND gates required to implement the function F = (x +

CuriousTab

CuriousTab

Home Aptitude

Discussion

Home ‣ Electronics and Communication Engineering ‣ Digital Electronics Comments

Question
Minimum number of 2-input NAND gates required to implement the function F = (x + y) (Z + W) is
Options
A. 3
B. 4
C. 5
D. 6

Correct Answer

4

Explanation

F = (x + y) (z + w) = xy.(z + w)

= xyz + xyw

= Minimum number of 2-input NAND gates required to implement the function F = (x + y) (Z + W) is 3 4 5 minimum no. of 2 input NAND gate.

Digital Electronics problems

Search Results

2. A carry look ahead adder is frequently used for addition because
Options
A. it costs less
B. it is faster
C. it is more accurate
D. is uses fewer gates

5. A JK flip flop has t_pd= 12 ns. The largest modulus of a ripple counter using these flip flops and operating at 10 MHz is
Options
A. 16
B. 64
C. 128
D. 256

6. The basic storage element in a digital system is
Options
A. flip flop
B. counter
C. multiplexer
D. encoder

7. A counter type A/D converter contains a 4 bit binary ladder and a counter driven by a 2 MHz clock. Then conversion time
Options
A. 8 ? sec
B. 10 ? sec
C. 2 ? sec
D. 5 ? sec

8. Decimal 43 in hexadecimal and BCD number system is respectively.
Options
A. B2, 01000011
B. 2B, 01000011
C. 2B, 00110100
D. B2, 01000100

10. Which of the following is taken as reference antenna for directive gain?
Options
A. Half wave dipole
B. Elementary doublet
C. Isotropic
D. Infinitesimal dipole

Comments

There are no comments.

More in Electronics and Communication Engineering: