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Digital Electronics
Comments
Question
In a BCD to 7 segment decoder the minimum and maximum number of outputs active at any time is
Options
A. 2 and 7
B. 3 and 7
C. 1 and 6
D. 3 and 6
Correct Answer
2 and 7
Explanation
Minimum number of outputs when input is decimal 1 and maximum number of outputs when input is decimal 8.
Digital Electronics problems
Search Results
1. The circuit in the given figure is
Options
A. positive logic OR gate
B. negative logic OR gate
C. negative logic AND gate
D. positive logic AND gate
Show Answer
Scratch Pad
Discuss
Correct Answer: negative logic OR gate
Explanation:
Since V(1) is lower state than V(0) it is a negative logic circuit. Since diodes are in parallel, it is an OR gate.
2. 7BF
16
= __________
2
Options
A. 0111 1011 1110
B. 0111 1011 1111
C. 0111 1011 0111
D. 0111 1011 0011
Show Answer
Scratch Pad
Discuss
Correct Answer: 0111 1011 1111
Explanation:
7BF
16
= 7 x 16
2
+ 11 x 16
1
+ 15 x 16
0
= 1983 in decimal = 0111 1011 1111 in binary.
3. BCD input 1000 is fed to a 7 segment display through a BCD to 7 segment decoder/driver. The segments which will lit up are
Options
A.
a, b, d
B.
a, b, c
C. all
D.
a, b, g, c, d
Show Answer
Scratch Pad
Discuss
Correct Answer: all
Explanation:
1000 equals decimal 8 Therefore all segments will lit up.
4. In a 7 segment display, LEDs
b
and
c
lit up. The decimal number displayed is
Options
A. 9
B. 7
C. 3
D. 1
Show Answer
Scratch Pad
Discuss
Correct Answer: 1
Explanation:
5. A 12 bit ADC is used to convert analog voltage of 0 to 10 V into digital. The resolution is
Options
A. 2.44 mV
B. 24.4 mV
C. 1.2 V
D. none of the above
Show Answer
Scratch Pad
Discuss
Correct Answer: 2.44 mV
Explanation:
.
6. For the gate in the given figure the output will be
Options
A. 0
B. 1
C. A
D.
A
Show Answer
Scratch Pad
Discuss
Correct Answer:
A
Explanation:
If A = 0, Y = 1 and A = 1, Y = 0 Therefore Y =
A
.
7. AB + A
B
=
Options
A. B
B. A
C. 1
D. 0
Show Answer
Scratch Pad
Discuss
Correct Answer: A
Explanation:
AB + A
B
= A(B +
B
) = A . 1 = A.
8. A three state switch has three outputs. These are
Options
A. low, low and high
B. low, high, high
C. low. floating, low
D. low, high, floating
Show Answer
Scratch Pad
Discuss
Correct Answer: low, high, floating
Explanation:
Third state is floating.
9. The circuit of the given figure realizes the function
Options
A. Y = (
A
+
B
) C +
DE
B. Y =
A
+
B
+
C
+
D
+
E
C. AB + C +DE
D. AB + C(D + E)
Show Answer
Scratch Pad
Discuss
Correct Answer: Y = (
A
+
B
) C +
DE
Explanation:
or
Y = (
A
+
B
)C +
DE
.
10. In register index addressing mode the effective address is given by
Options
A. index register value
B. sum of the index register value and the operand
C. operand
D. difference of the index register value and the operand
Show Answer
Scratch Pad
Discuss
Correct Answer: sum of the index register value and the operand
Explanation:
4 = 2
2
, in up scaling digit will be shifted by two bit in right direction.
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