In the circuit shown, in switch S is open for a long time and is closed at t = 0. The current i(t) for t ? 0⁺ is

Routh array

There is negative number present in first column. Thus network is unstable.

Probability of no-error + probability one error

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Statement 1 is false, since f{h(t)e^3t} corresponds to the value of the Laplace transform of h(t) at s = 3.

If this converges, it implies that s = - 3 is in the ROC.

A casual and stable system must always have its ROC to the right of all its poles. However, s = - 3 is not to the right of the pole at s = - 2.

Statement 2 is false, because it is equivalent to stating that H(0) = 0. This contradicts the fact that H(s) does not have a zero at the origin.

Statement 3 is false. If h(t) is of finite duration, then if its Laplace transform has any points in its ROC, ROC must be the entire s-plane.

However, this is not consistent with H(s) having a pole at s = - 2.

Statement 4 is false. If it were true, then H(s) has a pole at s = - 2, it must also have a pole at s = 2.

This is inconsistent with the fact that all the poles of a causal and stable system must be in the left half of the s-plane.

Distortion less

a = RG and Z₀ = RG ?

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Since autocorrelation function and power spectral density bears a Fourier transform relation, then since required in frequency domain will five rectangular convolutions in time domain thus it is triangular function.

Apply Mesh analysis

Apply KVL to mesh 2

-2 + V_y + 1 = 0

? V_y = 1

Apply KVL to mesh 1

? -8 + V_x + 2 = 0

? V_x = 6 V

Apply KVL to mesh 3

-1 + V_z -2 = 0

? V_z = 3 V.

s = x² - e^x

x(t) = cos t.

Z_s = R_s + (R_B || Br_s)

r_c = 2.475 = 1.258 kV

Zener diode is used only in voltage regulator circuits.

Emitter is n type and emits electrons which diffuse through the base.