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  • Question

  • Suppose that the modulating signal is m(t) = 2cos (2pfmt) and the carrier signal is xC(t) = AC cos(2pfct), which one of the following is a conventional AM signal without over modulation?


  • Options
  • A. x(t) = Acm(t)cos(2pfct)
  • B. x(t) = Ac [1 + m(t)]cos (2pfct)
  • C. Suppose that the modulating signal is m(t) = 2cos (2pfmt) and the carrier signal is xC(t) = AC cos(2
  • D. x(t) = Accos(2pfmt)cos(2pfct) + Acsin(2pfmt)sin(2pfct)

  • Correct Answer
  •  

    Explanation
    Suppose that the modulating signal is m(t) = 2cos (2pfmt) and the carrier signal is xC(t) = AC cos(2

    Suppose that the modulating signal is m(t) = 2cos (2pfmt) and the carrier signal is xC(t) = AC cos(2

    (C) is without over modulation.

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