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  • Question

  • The analog signal given below is sampled at 1200 samples per second. m(t) = 2 sin 120 pt + 3 sin 240 pt + 4 sin 360 pt + 5 sin 480 pt + 6 sin 600 pt + 7 sin 720 pt. The folding (maximum) frequency is __________ .


  • Options
  • A. 300 Hz
  • B. 360 Hz
  • C. 600 Hz
  • D. 480 Hz

  • Correct Answer
  • 600 Hz 

    Explanation
    Folding frequency (max.) =The analog signal given below is sampled at 1200 samples per second. m(t) = 2 sin 120 pt + 3 sin 240 = 600 Hz.

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