The final value theorem is �f(t) = �-1F(s) = f(t) �[a f1(t) + bf2(t)] = aF1(s) +

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Correct Answer

Explanation

�f(t) =

�^-1F(s) = f(t)

�[a f₁(t) + bf₂(t)] = aF₁(s) + bF₂(s)

The final value theorem is �f(t) = �-1F(s) = f(t) �[a f1(t) + bf2(t)] = aF1(s) + bF2(s) where �[f(t

where The final value theorem is �f(t) = �-1F(s) = f(t) �[a f1(t) + bf2(t)] = aF1(s) + bF2(s) where �[f(t

�[f(t - T)] = e^-sT F(s)

�[e^-at f(t)] = F(s + a)

Initial value theorem The final value theorem is �f(t) = �-1F(s) = f(t) �[a f1(t) + bf2(t)] = aF1(s) + bF2(s) where �[f(t

Final value theroem The final value theorem is �f(t) = �-1F(s) = f(t) �[a f1(t) + bf2(t)] = aF1(s) + bF2(s) where �[f(t

Convolution Integral The final value theorem is �f(t) = �-1F(s) = f(t) �[a f1(t) + bf2(t)] = aF1(s) + bF2(s) where �[f(t

The final value theorem is �f(t) = �-1F(s) = f(t) �[a f1(t) + bf2(t)] = aF1(s) + bF2(s) where �[f(t

where t is dummy variable for t.