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  • Question
  • The system with given pole-zero diagram is
    The system with given pole-zero diagram is casual non-casual both sided not-possible Because no.of z


  • Options
  • A. casual
  • B. non-casual
  • C. both sided
  • D. not-possible

  • Correct Answer
  • not-possible 

    Explanation
    Because no.of zero is more than Pole, therefore when you find transfer function.

    Numerator power will higher than denominator, and such transfer functions is not realizable.


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    • 1. A voltage wave having 5% fifth harmonic content is applied to a series RC circuit. The percentage fifth harmonic content in the current wave will be

    • Options
    • A. 5%
    • B. more than 5%
    • C. less than 5%
    • D. equal or more than 5%
    • Discuss
    • 2. Let x(t) and y(t) with F.T. x(f) and y(f) respectively be related as shown in figure

      Then y(f) is

    • Options
    • A.
    • B.
    • C. -X(f/2)ej2pf
    • D. -X(f/2)e- j2pf
    • Discuss
    • 3. The signal defined by the equations f(t) = 0 for t < 0, f(t) = E for 0 ? t ? a and f(t) = 0 for t > a is

    • Options
    • A. a step function
    • B. a pulse function
    • C. a shifted step function originating at t = a
    • D. none of the above
    • Discuss
    • 4. If I (s) , the final value of i(t) is

    • Options
    • A. 5A
    • B. 12.5 A
    • C. 0.05 A
    • D. 1250 A
    • Discuss
    • 5. Two function g1(t) and g2(t) with correlation of 6 has average power of 4 and 5 respectively. The power of g1(t) + g2(t) is

    • Options
    • A. 9
    • B. 21
    • C. 3
    • D. 15
    • Discuss
    • 6. If £[f(t)] = F(s), then £[f(t - T)] =

    • Options
    • A. est F(s)
    • B. e-st F(s)
    • C.
    • D.
    • Discuss
    • 7. As per time displacement theorem in Laplace transformation, displacement in the time domain by T becomes

    • Options
    • A. division by s in the s domain
    • B. division by e-sT in the s domain
    • C. multiplication by s in the s domain
    • D. multiplication by e-sT in the s domain
    • Discuss
    • 8. An energy signal has G(f) = 10. Its energy density spectrum is

    • Options
    • A. 10
    • B. 100
    • C. 50
    • D. 20
    • Discuss
    • 9. A signal m(t) is multiplied by a sinusoidal waveform of frequency fc such that
      v(t)=m(t) cos 2pfct
      If Fourier transform of m(t) is M(f), Fourier transform of v(t) will be

    • Options
    • A. 0.5 M(f + fc)
    • B. 0.5 M(f - fc)
    • C. 0.5 M(f + fc) + 0.5 M(f - fc)
    • D. 0.5 M(f - fc) + 0.5 M(f - fc)
    • Discuss
    • 10. The analog signal m(t) is given below m(t) = 4 cos 100 pt + 8 sin 200 pt + cos 300 pt, the Nyquist sampling rate will be

    • Options
    • A. 1/100
    • B. 1/200
    • C. 1/300
    • D. 1/600
    • Discuss


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