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- Question
What would be the output of the following program? main() { float a = 0.7; if ( a < 0.7f ) printf ( " C "); else Printf ( " C++ "); }
- Correct Answer
- C++
- 1. What would be the output of the following program? main() { printf (" %d%d%d ", sizeof (3.14f), sizeof (3.14), sizeof (3. 141); } Discuss
- 2. Which error are you likely to get when you run the following program? main() { struct emp { char name[20]; float sal; }; struct emp e[10]; int i; for ( i = 0 ; i <= 9; i++) scanf ( "%s %f" , e[i].name, &e[i].sal ); } Discuss
- 3. In the following code in which order the functions would be called? a = ( f1 ( 23,14 ) * f2 ( 12/4) ) + f3() ; Discuss
- 4. What would be the output of the following program? main() { int i=2 ; printf ("\n%d%d", ++i, ++i ); } Discuss
- 5. What would be the output of the following program? main() { static int a[20]; int i = 0; a[i] = i++; printf ("\n%d%d%d", a[0], a[1], i); } Discuss
- 6. There is a mistake in the following code. Add a statement in it to remove it. main() { int a; a = f (10, 3.14) ; printf ( " %d ", a ); } f (int aa, float bb) { return ( ( float ) aa + bb ); } Discuss
- 7. Point out the error, if any, in the following program. main() { int a = 10; void f(); a = f(); printf ( "\n %d", a ); } void f() { printf ( "\n Hi "); } Discuss
- 8. Will the following function work? f1 ( int a, int b ) { return ( f2 (20) ); } f2 ( int a ) { return ( a * a ); } Discuss
- 9. Indicate what would the SWAP macro be expanded to on preprocessing. Would the code compile? #define SWAP (a, b, c ) (c t; t = a, a = b, b = t; ) main() { int x = 10, y = 20; SWAP (x, y, int ); printf ( " %d%d ", x, y); } Discuss
- 10. What would be the output of the following program assuming that the array beigns at location 1002? main() { int a[3][4] = { 1 , 2 , 3 , 4 5, 6 , 7, 8 9, 10 , 11, 12 }; Printf ("\n%u %u %u", a[0] + 1, *( a[0] + 1), *( *(a + 0) + 1) ); } Discuss
Programming problems
Search Results
Correct Answer: 4 8 10
Correct Answer: Floating point formats not linked
Correct Answer: The order may vary from compiler to compiler Here the multiplication will happen before the addition , but in which order the functions would be called is undefined In an arithmetic expression the parentheses tell the compiler which operands go with which operators but do not force the compiler to evaluate everything within the parentheses first
Correct Answer: Output may vary from compiler to compiler The order of evaluation of the arguments to a function call is unspecified
Correct Answer: 0 0 1 That's what some of the compilers would give But some other compiler may give a different answer The reason is, when a single expression causes the same object to be modified and then inspected the behaviour is undefined
Correct Answer: Add the following function prototype in main (): float f ( int, float );
Correct Answer: In spite of defining the function f() as returning void, the program is trying to collect the value returned by f() in the variable a
Correct Answer: Yes
Correct Answer: ( int t ; t = a, a = b, b = t ;); This code won't compile since declaration of t cannot occur within parentheses
Correct Answer: 1004 2 2
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