If the binary equivalent of 5.375 in normalized form is 0100 0000 1010 1100 0000 0000 0000 0000, what would be the output of the following program?

main()

{

    float a = 5.375 ;

    char *p;

    int i;

    p = ( char* ) &a ;

    for ( i = 0; i <= 3 ; i++ )

          printf ( " %02x ", (unsigned char ) p[i] );

}

Correct Answer: Here in this declaration public static void main string[] args, each keyword has its importance 1 public - Here public is an access specifier which allows the main method to be accessible everywhere 2 static - static helps the main method to get loaded without getting called by any instance/object 3 void - void clarifies that the main method will not return any value 4 main - It's the name of the method 5 String[] args - Here we are defining a String array to pass arguments at the command line args is the variable name of the String array

Correct Answer: Encryption

Explanation:

The coding or scrambling of data so that humans cannot read them is known as encryption.

Correct Answer: An explicit intent explicitly defines the activity the developer wishes to start Script code : Intent myIntent = new Intent(this, MyNewActivityclass); startActivity(myIntent);

Correct Answer: 100

Explanation:

Preprocessor executes as a seperate pass before the execution of the compiler. So textual replacement of clrscr() to 100 occurs.The input program to compiler looks like this :

main ()

{

100;

printf("%d\n",100);

}

Note: 100; is an executable statement but with no action. So it doesn't give any problem.

Correct Answer: =

Explanation:

The valid escape codes in programming languages are ', ", \, n, or t are the valid escape codes. 

 

For example, the sequence \n usually represents a newline, while the escape sequence \\ represents a backslash, \t usually represents a newtab.

Correct Answer: 0..1..2

Explanation:

enum assigns numbers starting from 0, if not explicitly defined.

Correct Answer: The Lord of the Rings

Correct Answer: Error occurs because we have mixed the ANSI prototype with K & R style of function definition When we use ANSI prototype for a function and pass a float to the function it is promoted to a double When the function accepts this double into a float a type mismatch occurs hence the error The remedy for this error could be to define the function as : int fun (float aa) { }

Correct Answer: Looping

Correct Answer: Compilation error

Explanation:

Size of any array in c cannot be constantan variable.