Given series is A F Z U G L T _
Starts with A
A + 5 letters = F
go to end of alphabet= Z
Z - 5 letters = U
from F go one more to G + 5 letters = L
from U go one back to U, T - 5 letters = O
Second Method ::
Change the letters to their corresponding number.
A=1
B=2
C=3
...
Z=26
A F Z U G L T _
1 6 26 21 7 12 20 ?
Look at the pattern: the 1st and 3rd numbers = 27, 1+26
the 2nd and 4th numbers = 27, 6+21
the 5th and 7th numbers = 27,
so the 6 and 8th would also equal 27.
27 - 12 = 15,
so the letter is O.
Here given that 9 = 63, 8 = 48, 7=35, ...
The given question follows a pattern that
9 x (9 - 2) = 9 x 7 = 63
8 x (8 - 2) = 8 x 6 = 48
7 x (7 - 2) = 7 x 5 = 35
Similarly, 4 x (4 - 2) = 4 x 2 = 8.
How many times can you subtract 10 from 100, for this if we go through logically, it is only 1 time. For the first time if we subtract 10 from 100, then there will no 100 to subtract from.
Hence, it is only 1 time we can subtract 10 from 100.
The given puzzle follows a pattern that,
Number - <last digit> <sum of all digits>.
111 - 13
112 - 24
113 - 35
So
117 - 79
If you add all the terms of the LHS of equality, then the last letter of the sum written in words would give you the RHS.
1 + 1 + 1 + 1 = 4 = FOUR
2 + 2 + 2 + 2 = 8 = EIGHT
3 + 3 + 3 + 3 = 12 = TWELVE
4 + 4 + 4 + 4 = 16 = SIXTEEN
So, following the same pattern.
5 + 5 + 5 + 5 = 20 = TWENTY
That gives us our answer to 5 5 5 5 = "Y".
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