The degree of dissociation ( ? ) of a weak electrolyte, AxBy is related to van't

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Question
The degree of dissociation ( ? ) of a weak electrolyte, AxBy is related to van't Hoff factor (i) by the expression: 1. ?=x+y+1i-1 2.?=x+y-1i-1 3. ?=i-1x+y+1 4. ?=i-1x+y-1
Options
A. 1 is correct
B. 2 is correct
C. 3 is correct
D. 4 is correct

Correct Answer

4 is correct

Explanation

Van't Hoff factor (i) = $\frac{O b s e r v e d C o l l i g a t i v e P r o p e r t y}{N o r m a l C o l l i g a t i v e P r o p e r t y}$

$\begin{matrix} A_{x} B_{y} \\ 1 - ? \end{matrix} ? \begin{matrix} x A^{+ y} \\ x ? \end{matrix} + \begin{matrix} y B^{- x} \\ y ? \end{matrix}$

Total Moles = $1 - ? + x ? + y ?$ = $1 - ? (x + y - 1)$

$i = \frac{1 + ? (x + y - 1)}{1}$

$? ? = \frac{i - 1}{x + y - 1}$

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AIEEE