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  • Question
  • A polygenic trait is controlled by 3 genes A, B and C. In a cross AaBbCc x AaBbCc, the phenotypic ratio of the offsprings was observed as 1 : 6 : m : 20 : m : 6 : 1. What is the value of m?


  • Options
  • A. 10
  • B. 15
  • C. 18
  • D. 24

  • Correct Answer
  • 15 

    Explanation

    Here crossing is AaBbCc x AaBbCc

    As it is trihybrid cross,

    we know, Number of zygotes formed =  4 n ,   where   n   =   3

    4 3   =   64

    Given ratio of offsprings = 1 : 6 : m : 20 : m : 6 : 1

    Now,  1 + 6 + m + 20 + m + 6 + 1 = 64

    34 + 2m = 64

    2m = 30

    => m = 15.

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