Let us assume that the N number of people have only TV.
According to question,
? (40 ? P) + P + 10 + 15 + (50 ? P) = 100
? 115 ? 2P + P = 100
? P = 115 ? 100 = 15
? Only TV = 75 ? 15 ? 10 ? 15 = 35
Let age of daughter = N yr
? Age of Meena = 8N yr
Accounting to the question, (8N + 8)/(N + 8) = 10/3
? 24N + 24 = 10N + 80
? 14N = 56
? N = 4
Hence, Meena's present age = 4 x 8 = 32 yr
? [(9 + 6)/(9 - 6)] x v = 12
? v = 2.4 km/hr
Let the respective ages of Yogesh, Prakash, and Sameer 10 years's ago be 2x, 3x and 4 x years.
? Present age of Yogesh = (2x + 10 ) years
? Present age of Prakash = (3x + 10 ) years
? Present age of sameer = (4x + 10) years
According to question,
(2x + 10) + (3x + 10) + (4x + 10 ) = 93
? 9x + 30 = 93
? 9x = 63
? x = 7
? Present age of Sameer = 4x + 10 = 28 + 10 = 38 years .
Let the present age of man be x years and the age of his son be y years.
From 1st condition,
x = 5y .....(i)
From 2nd condition ,
(x + 4 ) + (y + 4) = 56
? x + y + 8 = 56
? x + y = 48 ... (ii)
Putting x = 5y in equation (ii)
5y + y = 48
? 6y = 48
? y = 8
? Age of son = 8 years
According to the formula.
Required time = (x + y)/(u - v)
Here , x = 50 m , y = 65 m , u = 18 m/s and v = 17 m/s
? Required time = (50 + 65)/(18 - 17) = 115/ 1 = 115 s
? Age of Raju when he got the job = 17 + 3 + 2 + 1 = 23 yr
? Age of Raju at the time of marriage = 23 + 3 = 26 yr
Let the present age of father be x years and the sum of present ages of 2 sons be y years.
? x = 3y ...(i)
? (x + 20) = (y + 20 + 20) ...(ii) [20 will be added twice as for 2 children]
Solving (i) and (ii), we get
x = 30 years
Let the average age of A, B and C be N years.
? Total age of A, B and C = 3 x N = 3N years
Now, according to the question,
? 3N - (2N + N/2) = 5
? N = 10 years.
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.